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3 years ago

The function N(X) = 90(0.86)* + 69 can be used to predict the temperature of a

Mathematics

1 answer:

dezoksy [38]3 years ago

4 0

Answer: -8.93

Step-by-step explanation:

Given the function:

N(X) = 90(0.86)^x+ 69

X in the interval [0, 6]

For X = 0

N(0) = 90(0.86)^0 + 69

90 + 69 = 159

For X = 6

N(6) = 90(0.86)^6 + 69

90(0.404567235136) + 69

= 105.41105116224

Therefore, average change of change in temperature ;

(temp 2 - temp 1) / ( time 2 - time)

(105.41105116224 - 159) / (6 - 0)

= - 53.58894883776 / 6

= - 8.93149147296

= - 8.93

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Daniel [21]

Answer:

1/2

Step-by-step explanation:

if you look at a unit circle, sin(\pi/6) is $\sqrt{3}/2$ so cos of (\pi/6/2) would be \pi/3, and cos of (\pi/3) is 1/2

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3 years ago

under a dilation, the point (2,6) is moved to (6,18) what is the scale factor of the dilation? enter your answer in the box

Anestetic [448]

Step-by-step explanation:

The equation of line passing through the two points is $\frac{y-y_{1} }{x-x_{1} }=\frac{y_{2} -y_{1}}{x_{2} -x_{1}}$

When substituted,the equation becomes $\frac{y-6}{x-2}=\frac{18-6}{6-2}$

which when simplified is $y=3\times x$

The line clearly passes through origin.

The distance between two points is $\sqrt{(y_{1}-y_{2} )^{2}+(x_{1}- x_{2} )^{2}}$

Distance between origin and $(2,6)$ is $\sqrt{40}$ .

Distance between origin and $(6,18)$ is $\sqrt{360}$

Scale factor is $\frac{distance\text{ }of\text{ }p_{2}\text{ from origin}}{distance \text{ } of \text{ } p_{1}\text{ from origin}}$

So,scale factor is $\frac{\sqrt{360} }{\sqrt{40} }$

which when simplified becomes 3.

6 0

3 years ago

Help me<br> On this pleaseee

Evgen [1.6K]

2 rectangle shaped
1) Length = 160 mi ; Width = 40 mi
2) Length = 440 mi - 160 mi ; Width = 240 mi - 70 mi

1 triangle shape
1) base = 70 mi ; height = 440 mi - 160 mi

Area Rectangle 1 = 160 mi * 40 mi = 6,400 mi²
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Area Triangle 1 = ((440 mi - 160 mi) * 70mi)/2 = (280mi * 70mi)/2 = 9,800 mi²

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3 years ago

The function g(x) is shown in the graph at right. The function g(x) is a transformation of the parent function f(x)=x^2. Based o

Ivahew [28]

Answer: choice B

Step-by-step explanation:

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2 years ago

A random sample of size 15 taken from a normally distributed population revealed a sample mean of 75 and a sample variance of 25

GREYUIT [131]

Answer:

The upper limit of a 95% confidence interval for the population mean would equal 83.805.

Step-by-step explanation:

The standard deviation is the square root of the variance. Since the variance is 25, the sample's standard deviation is 5.

We have the sample standard deviation, not the population, so we use the t-distribution to solve this question.

T interval:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 15 - 1 = 14

Now, we have to find a value of T, which is found looking at the t table, with 14 degrees of freedom(y-axis) and a confidence level of 0.95( $t_{95}$ ). So we have T = 1.761

The margin of error is:

M = T*s = 1.761*5 = 8.805.

The upper end of the interval is the sample mean added to M. So it is 75 + 8.805 = 83.805.

The upper limit of a 95% confidence interval for the population mean would equal 83.805.

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3 years ago