The mole fraction of urea in a solution that contain 2.1 mol Urea and 4.4 mole of water is 0.32
calculation
mole fraction = moles of urea/ total mole
moles of urea = 2.1 mole
calculate the total mole
= 2.1 mole + 4.4 mole = 6.5
Mole fraction is therefore = 2.1/.6.5 = 0.32
Answer:
the limiting reagent is butane
Explanation:
5C₄H₁₀ + 25O₂ → 20CO₂ + 5H₂0
Answer:
The correct answer is 0.89 mol.
Explanation:
At STP (Standard Temperature and Pressure) conditions, 1 mol of an ideal gas occupies a volume of 22.4 L. If we assume STP conditions, we can consider a convertion factor of 1 mol/22.4 L to convert the volume of NO₂ from liters to moles:
20,00 L x 1 mol/22.4 L = 0.89 mol
So, at STP, we would have 0.89 mol of NO₂
Answer:
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