When carbon is burned in air carbon iv oxide gas is formed.
C (s) + O2 (g) = CO2(g) ΔH = - 393.5 kj/mol
The enthalpy change of the reaction is -393.5 j/mol which means that when one mole of carbon is completely burnt in air then 393.5 j of energy is evolved.
Thus, 1 mole = -393.5 j , then for 480 kj
= 480 × 1/393.5
= 1.2198 moles
1 mole of carbon iv oxide is equal to 44 g
thus, 1.2198 moles will be 1.2198 × 44 = 53.6712 g of CO2
Answer:
Sulfur's Atomic #: 16
Fluorine's Atomic #: 9
Antimony's Atomic #: 51
Silver's Atomic #: 47
Rubidium's Atomic #: 37
Copper's Atomic #: 29
Tin's Atomic #: 50
Mercury's Atomic #: 80
Promethium's Atomic #: 61
