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Margaret [11]
3 years ago
8

In chemical formulas, there are often subscript numbers (such as the 2 in H2O, or the 6, 12, and 6 in C6H12O6).

Chemistry
1 answer:
Roman55 [17]3 years ago
8 0

Answer : The correct option is, Subscript numbers tell us how many of the element to their upper-left there are in the molecule.

Explanation :

Subscript number : It indicates that the total number of atoms of an element present in a molecule.

While witting a chemical formula, first we have to write the symbol of an element and then write the number in the bottom of the symbol.

For example :

C_6H_{12}O_6 is the chemical formula of the glucose molecule. The glucose molecule is made up of six carbon atoms, twelve hydrogen atoms and 6 oxygen atoms.

The number 6 of carbon atom is written after and in the bottom (lower-right) of the symbol of carbon element (C). Similarly, the number 12 is written lower-right of the symbol of hydrogen element (H) and the number 6 is written lower-right of the symbol of oxygen element (O).

Therefore, the subscript numbers tell us how many of the element to their upper-left there are in the molecule.

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An atom of carbon has 4 electrons in its outermost shell, which means that 
<span>its ionic charge is 4+ or 4-
</span>Si is in same group as carbon so its also 4+ or 4-
Germanium is 4+.
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3 years ago
When 60 mL of 0.22 M NH4Cl is added to 60 mL of 0.22 M NH3, relative to the pH of the 0.10 M NH3 solution the pH of the resultin
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Answer:

Will be more acidic

Explanation:

The equilibrium of NH3 in water is:

NH3(aq) + H2O(l) ⇄ NH4⁺(aq) + OH⁻(aq).

Where equilibrium constant, Kb, is:

Kb = 1.85x10⁻⁵ = [NH4⁺] [OH⁻] / [NH3]

From 0.10M NH3, the reaction will produce X of NH4⁺ and X of OH⁻ and Kb will be:

1.85x10⁻⁵ = [X] [X] / [0.10M]

1.8x10⁻⁶ = X²

X = 1.34x10⁻³ = [OH⁻]

As pOH = -log[OH⁻] = 2.87

And as pH = 14 - pOH

pH of the 0.10M NH3 is 11.13

Now, to find the pH of the NH4Cl and NH3 we need to use H-H equation for bases:

pOH = pKb + log [NH4⁺] / [NH3]

<em>Where pKb is -log Kb = 4.74 and [] are moles of both compounds.</em>

<em />

Moles of [NH4⁺] = [NH3] = 60mL, 0.060L*0.22M = 0.0132moles:

pOH = 4.74 + log [0.0132] / [0.0132]

pOH = 4.74

pH = 14 - 4.74 = 9.26

That means the pH of the resulting solution will be more acidic

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