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Margaret [11]
3 years ago
8

In chemical formulas, there are often subscript numbers (such as the 2 in H2O, or the 6, 12, and 6 in C6H12O6).

Chemistry
1 answer:
Roman55 [17]3 years ago
8 0

Answer : The correct option is, Subscript numbers tell us how many of the element to their upper-left there are in the molecule.

Explanation :

Subscript number : It indicates that the total number of atoms of an element present in a molecule.

While witting a chemical formula, first we have to write the symbol of an element and then write the number in the bottom of the symbol.

For example :

C_6H_{12}O_6 is the chemical formula of the glucose molecule. The glucose molecule is made up of six carbon atoms, twelve hydrogen atoms and 6 oxygen atoms.

The number 6 of carbon atom is written after and in the bottom (lower-right) of the symbol of carbon element (C). Similarly, the number 12 is written lower-right of the symbol of hydrogen element (H) and the number 6 is written lower-right of the symbol of oxygen element (O).

Therefore, the subscript numbers tell us how many of the element to their upper-left there are in the molecule.

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4 0
3 years ago
A compound has a percent composition of 81.71% C and 18.29% H. What is the empirical formula of this compound?
SCORPION-xisa [38]

Considering the definition of empirical formula, the empirical formula is C₃H₈.

<h3>Definition of empirical formula</h3>

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

<h3>Empirical formula in this case</h3>

In this case, in first place you know the percent composition:

  • C: 81.71 %
  • H: 18.29%

Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 81.71 grams of carbon and 18.29 grams of hydrogen H.

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

  • C: \frac{81.71 grams}{12\frac{grams}{mole} }= 6.81 moles
  • H:\frac{18.29 grams}{1\frac{grams}{mole} }= 18.29 moles

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

  • C: \frac{6.81 moles}{6.81 moles}= 1
  • H:\frac{18.29 moles}{6.81 moles}= 2.68 ≅ \frac{8}{3}

To express this relationship in the form of simple integers, it is necessary to multiply by a simple number to achieve this:

  • C: 1×3  =3
  • H:≅ \frac{8}{3}×3= 8

Therefore the C: H mole ratio is 3: 8

Finally, the empirical formula is C₃H₈.

Learn more about empirical formula:

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#SPJ1

4 0
2 years ago
Pls help and match them
slega [8]

Answer:

Simile: C

Personification: D

Symbol: A

Hyperbole: B

Metaphor: E

Explanation:

3 0
3 years ago
Drag the tiles to the correct locations. Each tile can be used more than once, but not all tiles will be used. One or more locat
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Answer:             xx           xx

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Explanation:

Sorry for the structure, but since Oxygen and Sulfur belong to group of six they want to share two electrons. Carbon belonging to group four wants to share 4 since its valence shell has four electrons.

Therefore the resulting Lewis structure is linear (like carbon dioxide) with two pairs of lone pairs in each O and S atoms and 0 lone pairs in carbon and two double bond.

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3 years ago
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Ne, c4h10, is a component of natural gas that is used as fuel for cigarette lighters. the balanced equation of the complete comb
Simora [160]
<span>3.68 liters First, determine the number of moles of butane you have. Start with the atomic weights of the involved elements: Atomic weight carbon = 12.0107 Atomic weight hydrogen = 1.00794 Atomic weight oxygen = 15.999 Molar mass butane = 4*12.0107 + 10*1.00794 = 58.1222 g/mol Moles butane = 2.20 g / 58.1222 g/mol = 0.037851286 Looking at the balanced equation for the reaction which is 2 C4H10(g)+13 O2(g)→8 CO2(g)+10 H2O(l) It indicates that for every 2 moles of butane used, 8 moles of carbon dioxide is produced. Simplified, for each mole of butane, 4 moles of CO2 are produced. So let's calculate how many moles of CO2 we have: 0.037851286 mol * 4 = 0.151405143 mol The ideal gas law is PV = nRT where P = Pressure V = Volume n = number of moles R = Ideal gas constant ( 0.082057338 L*atm/(K*mol) ) T = absolute temperature (23C + 273.15K = 296.15K) So let's solve the formula for V and the calculate using known values: PV = nRT V = nRT/P V = (0.151405143 mol) (0.082057338 L*atm/(K*mol))(296.15K)/(1 atm) V = (3.679338871 L*atm)/(1 atm) V = 3.679338871 L So the volume of CO2 produced will occupy 3.68 liters.</span>
4 0
3 years ago
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