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Alex17521 [72]
3 years ago
10

2. Water is a great example of a molecule with polar covalent bonds. How does this bond affect the

Chemistry
2 answers:
Rzqust [24]3 years ago
8 0

Answer :

Example of polar covalent molecules H-O-H(water), ammonia

Explanation:

The presence of intermolecular Hydrogen bonding makes the boiling point of water unexpectedly high, and the polar covalent nature makes it dissolve polar solute/compound

dimulka [17.4K]3 years ago
6 0

Answer:

Explanation:

The constituent of a water molecule is one oxygen atom and two hydrogen atom. Oxygen is highly electronegative ( ability to pull electron closer to itself in a covalent bond) compare to hydrogen and as such it creates two poles with oxygen been partially negative and hydrogen been partially positive.  This attributes allow water to dissolve polar substances such sodium chloride, sodium hydroxide. When this substance are added to water, they are pull apart with positive sodium ion attracted to the partially positive oxygen and the chloride ions attracted to the partially positive hydrogen.

The polarity of water ice is able to float in water because of the polar nature as the molecules is extended as far as possible and are held together by the hydrogen bond. Water expands when its freezes and it  density decreases

The polar nature also of its molecules also contributes to its high boiling, freezing point and strong surface tension.

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What were the first galaxies made of
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5 0
3 years ago
Which rule for assigning oxidation numbers IS correct?
Vilka [71]

Answer:

B.) Oxygen is usually -2

Explanation:

Hydrogen is usually +1.

A pure group 1 element is not always +1.

A monoatomic ion can be a range of numbers. However, it must be a charge other than 0.

3 0
2 years ago
A certain gas is present in a 10.0 LL cylinder at 4.0 atmatm pressure. If the pressure is increased to 8.0 atmatm the volume of
ICE Princess25 [194]

Answer:

The gas obeys Boyle’s law and the value of k_i\&k_f both are equal to 40.0 atm L.

Explanation:

Initial volume of the gas = V_1=10.0 L

Initial pressure of the gas = P_1=4.0 atm

Final volume of the gas = V_2=5.0 L

Final pressure of the gas = P_2=8.0 atm

This law states that pressure is inversely proportional to the volume of the gas at constant temperature.  

PV=k

The equation given by this law is:

P_1V_1=P_2V_2

P_1\propto \frac{1}{V_1}

P_1V_1=k_i

k_i=4.0 atm\times 10.0 L = 40.0 atm L

P_2\propto \frac{1}{V_2}

P_V_2=k_f

k_f=8.0 atm\times 5.0 L = 40.0 atm L

k_i=k_f=40.0 atm L

The gas in the cylinder is obeying Boyle's law.

The gas obeys Boyle’s law and the value of k_i\&k_f both are equal to 40.0 atm L.

6 0
3 years ago
If the temperature on 244 mL of a gas is changed to 488 mL and 6 atm, at constant
Fittoniya [83]

Answer:

<h2>12 atm</h2>

Explanation:

To find the initial pressure we use the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the initial pressure

P_1 =  \frac{P_2V_2}{V_1}  \\

From the question we have

P_1 =  \frac{488 \times 6}{244}  =  \frac{2928}{244}  \\

We have the final answer as

<h3>12 atm</h3>

Hope this helps you

6 0
3 years ago
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