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Alex17521 [72]
2 years ago
10

2. Water is a great example of a molecule with polar covalent bonds. How does this bond affect the

Chemistry
2 answers:
Rzqust [24]2 years ago
8 0

Answer :

Example of polar covalent molecules H-O-H(water), ammonia

Explanation:

The presence of intermolecular Hydrogen bonding makes the boiling point of water unexpectedly high, and the polar covalent nature makes it dissolve polar solute/compound

dimulka [17.4K]2 years ago
6 0

Answer:

Explanation:

The constituent of a water molecule is one oxygen atom and two hydrogen atom. Oxygen is highly electronegative ( ability to pull electron closer to itself in a covalent bond) compare to hydrogen and as such it creates two poles with oxygen been partially negative and hydrogen been partially positive.  This attributes allow water to dissolve polar substances such sodium chloride, sodium hydroxide. When this substance are added to water, they are pull apart with positive sodium ion attracted to the partially positive oxygen and the chloride ions attracted to the partially positive hydrogen.

The polarity of water ice is able to float in water because of the polar nature as the molecules is extended as far as possible and are held together by the hydrogen bond. Water expands when its freezes and it  density decreases

The polar nature also of its molecules also contributes to its high boiling, freezing point and strong surface tension.

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Calculate the pH of a solution in which [OH–] = 4.5 × 10–9M.
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Answer:

5.65 is the pH.

Explanation:

I am assuming that you are asking for confirmation on your answer. The answer is 5.65.

You would do:

[pOH] = -log[OH-]

          = -log[4.5*10^-9]

         equals about 8.3468

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3 years ago
The solubility of KCl is 3.7 M at 20 °C. Two beakers each contain 100. mL of saturated KCl solution: 100. mL of 4.0 M HCl is add
JulijaS [17]

Answer:

a)The Ksp was found to be equal to 13.69

Explanation:

Terminology

Qsp of a dissolving ionic solid — is the solubility product of the concentration of ions in solution.

Ksp however, is the solubility product of the concentration of ions in solution at EQUILIBRIUM with the dissolving ionic solid.

Note that if Qsp > Ksp , the solid at a certain temperature, will precipitate and form solid. That means the equilibrium will shift to the left in order to attain or reach equilibrium (Ksp).

Step-by-step solution:

To solve this: 

#./ Substitute the molar solubility of KCl as given into the ion-product equation to find the Ksp of KCl.

#./ Find the total concentration of ionic chloride in each beaker after the addition of HCl. We pay attention to the amount moles present at the beginning and the moles added.

#./ Find the Qsp value to to know if Ksp is exceeded. If Qsp < Ksp, nothing will precipitate.

a) The equation of solubility equilibrium for KCL is thus;

KCL_(s) ---> K+(aq) + Cl- (aq)

The solubility of KCl given is 3.7 M.

Ksp= [K+][Cl-] = (3.7)(3.7) =13.69

The Ksp was found to be equal to 14.

In pure water KCl

Ksp =13.69 KCl =[K+][Cl-]

Let x= molar solubility [K+],/[Cl-] :. × , x

Ksp =13.69 = [K+][Cl-] = (x)(x) = x²

x= √ 13.69 = 3.7 M moles of KCl requires to make 100mL saturated solutio

37M moles/L

The Ksp was found to be equal to 14.

4.0 M HCl = KCl =[K+][Cl-]

Let y= molar solubility :. y, y+4

Ksp =13.69= [K+][Cl-] = (y)(y*+4)

* - rule of thumb

Ksp =13.69= [K+][Cl-] = (y)(y*+4)= y(4)

13.69=4y:. y= 3.42 moles/100mL

y= 34.2moles/L

8 M HCl = KCl =[K+][Cl-]

Let b= molar solubility :. B, b+8

Ksp =13.69= [K+][Cl-] = (b)(b*+8)

* - rule of thumb

Ksp =13.69= [K+][Cl-] = (b)(b*+8)= b(8)

13.69=8b:. b= 1.71 moles/100mL

17.1 moles/L

Therefore in a solution with a common ion, the solubility of the compound reduces dramatically.

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