Answer:
Explanation:
Q3.What did you observe about the wavelengths and frequencies of the different colors of light?
Q4. Do the frequencies of colors of light increase from red to violet?
Q5. What did you observe about the corresponding energies from red to violet?
wavelength times frequency =c=the speed of light
the higher the frequency, the shorter the wavelength
the different colors of visible light are our good friend ROY G BIV
RED ORANGE YELLOW GREEN BLUE INDIGO VIOLET
As we go from red to violet, the wavelength decreases and the energy increases because the wave is vibrating at a higher number of vibrations per secomd. This is what "frequency' means, how many vibrations are there per second, how FREQUENT are thee.
the higher the frequency the more energy because the wave is vibrating faster.
the equation that relates this is Energy = h times frequency, where h is
Planck's constant = 6.262 x 10^-27 ERG-SEC
the frequency of vibration and therefor the energy of visible electromagnetic radiation (light) increase as we go across
ROY G BIV
Part 1 : Answer is only B substance is soluble in water.
In this experiment undissolved mass of each substance was measured. According to the given data, undissolved mass of substance B at 20 °C is 10 g while A is 50 g. Since, the initial added mass of each substance is 50 g, we can see that substance A is not soluble in water since the undissolved mass is 50 g.
Part 2 : Substance A is not soluble in water and substance B is soluble in water.
According to the given data, the undissolved mass of substance A remains as same as initial added mass, 50 g throughout the temperature range from 20 ° to 80 °C. Hence, we can conclude that substance A is not soluble in water.
But, according to the data, undissolved mass of substance B at 20 °C is 10 g. That means, 40 g of substance B was dissolved in water. When the temperature increases the undissolved mass of substance B decreases. Hence, we can conclude that substance B is soluble in water and solubility increases with temperature.
[Ne] 3s² 3p⁴
Not sure if that’s right
<span>The answer to your question is the 3rd option </span>