Often, the simplest way to solve "ax2 + bx + c = 0" for the value of x is to factor the quadratic, set each factor equal to zero, and then solve each factor. But sometimes the quadratic is too messy, or it doesn't factor at all, or you just don't feel like factoring.
Answer:
I don't know ether
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given the geometrical series
∑ [infinity] n=2 (− 2) n−1
I think the correct series should be the sum from n = 2 to ∞ of (-2)^n-1
So,
∑(-2)^(n-1)...... From n = 2 to ∞
A. The first four terms
When n = 2
(-2)^(2-1) = (-2)^1 = -2
When n = 3
(-2)^(3-1) = (-2)^2 = 4
When n = 4
(-2)^(4-1) = (-2)^3 = -8
When n = 5
(-2)^(5-1) = (-2)^4 = 16
B. The series will diverge since the common ratio is not between 0 and 1
So, let use limit test
Lim as n →∞ (-2)^(n-1) = (-2)^∞ = ±∞
Since the limit is infinite, then the series diverges
C. Since her series diverges we can find the sum, the sum is infinite, so it will sum up to ±∞
answer:
center: (-2, 0)
radius: 5
explanation
re write that equation in the form if the standard circle equation
(x - ( -2))^2 + (y - 0)^2 = 5^2
therefore the circle properties are: (a,b) = -2, 0 and the radius is 5
Answer:
9
Step-by-step explanation: