Rise over run. as time increases the temperature rises. starting at 8am and -2°f.
At 12pm the temperature rose to 4°f.
that's a difference of 4 hours and 6 degrees. for every hour, it rose 1.5 degrees. the slope is 1.5/1
<u>ANSWER:
</u>
Rate per annum at which CI will amount from RS 2000 to RS 2315.35 in 3 years is 5%
<u>SOLUTION:
</u>
Given,
P = RS 2000
C.I = RS 2315.35
T = 3 years
We need to find the rate per annum. i.e. R = ?
We know that,
When interest is compound Annually:

Where p = principal amount
r = rate of interest
n = number of years



![$1+\frac{R}{100}=\sqrt[3]{1.157}$](https://tex.z-dn.net/?f=%241%2B%5Cfrac%7BR%7D%7B100%7D%3D%5Csqrt%5B3%5D%7B1.157%7D%24)



R = 5%
Hence, rate per annum is 5 percent.
Answer:
triangle A andC are the same
<em>Answer,</em>
<em><u>S = -16</u></em>
<em>Explanation,</em>
<em><u>Step 1: Simplify both sides of the equation.</u></em>
<em>13 + 11s = − 15 + 8s − 20</em>
<em>13 + 11s = − 15 + 8s + − 20</em>
<em>11s + 13 = (8s) + (</em><em><u>− 15</u></em><em> + </em><em><u>− 20</u></em><em>) </em><em>(Combine Like Terms)</em>
<em>11s + 13 = 8s + − 35</em>
<em>11s + 13 = 8s − 35</em>
<em><u>Step 2: Subtract 8s from both sides.</u></em>
<em>11s + 13 − 8s = 8s − 35 − 8s</em>
<em>3s + 13 = − 35</em>
<em>Step 3: Subtract 13 from both sides.</em>
<em>3s + 13 − 13 = − 35 − 13</em>
<em>3s = − 48</em>
<em><u>Step 4: Divide both sides by 3.</u></em>
<em>3s/3 = −48/3</em>
<em>s = -16</em>
<u><em>Hope this helps :-)</em></u>