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sergij07 [2.7K]
3 years ago
15

Zirconium tungstate is an unusual material because its volume shrinks with an increase in temperature for the temperature range

0.3 K to 1050 K (where it decomposes). In fact, the volumetric coefficient of thermal expansion is –26.4 × 10–6/K. Determine the ratio ΔV/V0 for the above mentioned temperature range. Express your answer in percent.
Physics
1 answer:
True [87]3 years ago
4 0

Answer:

2.771208%

Explanation:

\Delta V = Change of volume

V_0 = Initial volume

\Delta T = Change in temperature = (0.3-1050)

\beta = Volumetric coefficient of thermal expansion = -26.4\times 10^{-6}\ /K

Volumetric expansion of heat is given by

\frac{\Delta V}{V_0}=\beta \Delta T\\\Rightarrow \frac{\Delta V}{V_0}=-26.4\times 10^{-6}\times (0.3-1050)\\\Rightarrow \frac{\Delta V}{V_0}=0.02771208

Finding percentage

\frac{\Delta V}{V_0}=0.02771208\times 100=2.771208\%

The ratio of change of volume to initial volume is 2.771208%

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