Hi There, Buddy!
To solve this problem, let us divide the entire motion into 2 phases
1.) When the elevator is moving with an acceleration
2.) When the elevator has a deceleration
For the first half -
u = 0 , a = 0.6 , t = t1
v = 0.6(t1) ---------- ( 1 )
s = 1/2 x 0.6 x (t1)^2 = 0.3(t1^2) -------- ( 2 )
For the second half -
u = 0.6(t1) , a = -0.8 , v = 0
0.6 x (t1) = 0.8 (t2) ----> 3(t1) = 4(t2) ---------- ( 3 )
0.36(t1)^2 = 1.6 s2 ---------- ( 4 )
Now, we know that the total time taken is 10 seconds
------- t1 + t2 =10 , 3t1 = 4t2 ---- t1 = 40/7 , t2 = 30/7
Now, substitute values of t1 and t2 in s1 and s2 and add both s1 and s2 to get total distance travelled.
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