The answer is d. lead and sulfuric acid
Answer:
The number of atoms of aluminum contained in one square inch of the foil=6
Explanation:
Interpretation:
The number of atoms of aluminum contained in one square inch of the foil is to be calculated.
Concept introduction: relation to calculate a number of atoms contained in one square inch of the foil is given by:
NA/c=mNA/AA1
Where,
M=mass of aluminum
NA= Avogadro's number
AA= Atomic mass of aluminum
Given :
Mass of aluminum foil=0.3 g
M= 0.39g
Relation to calculate a mass of atoms contained in one square inch of the foil is given by:
NA/c= mNA/AA1
M= Mass of aluminum
NA= Avogadro's number
AA= Atomic mass of aluminum
Since,
Avogadro's number
=6
Is there supposed to be a graph or something?
Answer:
how many protons and neutrons in its atoms
Explanation:
