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2 years ago

A measure of how close a series of measurements are to one another.

1 answer:

7 0

Answer: Precision is a measure of how close a series of measurements are to one another. Precise measurements are highly reproducible, even if the measurements are not near the correct value. Darts thrown at a dartboard are helpful in illustrating accuracy and precision

Explanation: a if this wrong u fault u gave no detail

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During oxidation of ethanol to ethanol, the ethanol formed was found to be contaminated with unconverted ethanol, describe how y

Dafna1 [17]

The process of how we would obtain ethanal free from ethanol is described in the explanations below.

In Chemistry, Ethanol undergoes oxidation in the presence of sodium dichromate plus sulphuric acid to yield ethanal and water.

The procedure for achieving this in the laboratory is as follows;

Step 1; Measure a quantity of a solution of sodium dichromate acidified in a dilute sulphuric acid and pour into a test tube.

Step 2; Add excess ethanol. This is because if we don't do so there will be plenty of oxidizing agent to carry out a second operation which changes the aldehyde to ethanoic acid. However, we need only the aldehyde.

Step 3; When the aldehyde ethanal begins to form which will be evident by the change in the colour of solution from orange to green, then the mixture should be distilled from the test tube and tbethe aldehyde collevted so that it doesn't undergo additional oxidation into ethanoic acid.

Read more at; https://brainly.in/question/18574624

4 0

2 years ago

Read 2 more answers

How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density o

Rashid [163]

Answer:

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

Explanation:

Heat gain by ice = Heat lost by water

Thus,

Heat of fusion + $m_{ice}\times C_{ice}\times (T_f-T_i)=-m_{water}\times C_{water}\times (T_f-T_i)$

Where, negative sign signifies heat loss

Or,

Heat of fusion + $m_{ice}\times C_{ice}\times (T_f-T_i)=m_{water}\times C_{water}\times (T_i-T_f)$

Heat of fusion = 334 J/g

Heat of fusion of ice with mass x = 334x J/g

For ice:

Mass = x g

Initial temperature = 0 °C

Final temperature = 6 °C

Specific heat of ice = 1.996 J/g°C

For water:

Volume = 353 mL

$Density (\rho)=\frac{Mass(m)}{Volume(V)}$

Density of water = 1.0 g/mL

So, mass of water = 353 g

Initial temperature = 26 °C

Final temperature = 6 °C

Specific heat of water = 4.186 J/g°C

So,

$334x+x\times 1.996\times (6-0)=353\times 4.186\times (26-6)$

$334x+x\times 11.976=29553.16$

345.976x = 29553.16

x = 85.4197 kg

Thus,

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

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3 years ago

How many formula units are found in 2.10 gram of Mgo? (No units needed.)

disa [49]

Answer:

84.63924

Explanation:

one moles equals 40.30440

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3 years ago

What do Van der Waals forces do?

Greeley [361]

Weaken London dispersion forces and stronger dipole dipole forces

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3 years ago

Please...................

Elena L [17]

I’m not sure but I hope someone tell you

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2 years ago