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alekssr [168]
4 years ago
7

What happened when the P-waves traveled through the planet?

Chemistry
1 answer:
xxTIMURxx [149]4 years ago
6 0

Answer: It passes through both mantle and core, but are slowed and refracted at the mantle / core boundary at a depth of 2900 km.

Explanation:

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The atmosphere protects us from all of the following except (4 points)
denis-greek [22]

Global warming, Cosmic Background radiation (even though most is blocked not ALL), and pollution.

8 0
4 years ago
Why is methanol written as ch3oh instead of ch4o?​
Ahat [919]

Answer: Here comes the role of another formula, which we refer to as the structural formula and that is CH3OH for methanol. The structural formula gives us an additional information that carbon is attached to three hydrogen atoms and one oxygen atom.

3 0
3 years ago
A balloon has a pressure of 3.1 atm at a volume of 155 ml. if the temperature is held constant, what is the volume (ml) if the p
GarryVolchara [31]

Answer:

45.8 mL

Explanation:

If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.

P₁ = 3.1 atm                        P₂ = 10.5 atm

V₁ = 155 mL                       V₂ = ? mL

P₁V₁ = P₂V₂                                                 <----- Boyle's Law equation

(3.1 atm)(155 mL) = (10.5 atm)V₂                <----- Insert values

480.5 = (10.5 atm)V₂                                  <----- Multiply 3.1 and 155

45.8 = V₂                                                    <----- Divide both sides by 10.5

4 0
2 years ago
Two pipes with 1 meter diameters join to become one pipe with 2 meter diameter. Water was flowing in first pipe at 500 kg/s and
zloy xaker [14]

Answer:

The mass flow rate at the exit of the 2 meter diameter pipe is 1442 kg/s

Explanation:

If the oil is flowing in the 1m diameter pipe at 0.8 m/s, we can calculate the flow as

Q=\bar{v}*A=\bar{v}*(\pi/4*D^{2} )=0.8m/s*0.785m^{2} =0.628m^{3}/s

The mass flow is

M=\rho*Q=1500 kg/m3*0.628m3/s=942kg/s

The mass flow rate at the exit of the 2 meter diameter pipe is

M=M_w+M_o=500 kg/s+942kg/s=1442kg/s

3 0
3 years ago
What is the effect of the following on the volume of 1 mol of an ideal gas? The temperature changes from 305 K to 32°C and the p
ryzh [129]

Answer:

The volume increases by 100%.

Explanation:

<u>Step 1:</u> Data given

Number of moles ideal gas = 1 mol

Initial temperature = 305 K

Final temperature = 32°C + 273.15 = 305.15 K

Initial pressure = 2 atm

final pressure = 101 kPa = 0.996792 atm

R = gasconstant = doesn't change

V1 = initial volume

V2= the final volume

<u>Step 2: </u>Calculate volume of original gas

P*V = n*R*T

(P*V)/ T = constante

(P1 * V1) / T1 = (P2 * V2)/ T2

In this situation we have:

(2atm * V1)/ 305  = (0.996792 *V2) / 305.15

0.006557*V1 = 0.003266*V2

V2 = 2*V1

We see that the final volume is twice the initial volume. So the volume gets doubled. The volume increases by 100%.

7 0
3 years ago
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