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Sonja [21]
3 years ago
15

Which will dissolve faster in water rock salt or granulated salt

Chemistry
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

Salt!!!

Explanation:

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What can not be separated easily or, sometimes at all
BabaBlast [244]
Pure Substances cannot be separated easily or, sometimes at all.

I hope this is the answer you were looking for and that it helps!! :)
8 0
3 years ago
Which best describes the field of chemistry?
qaws [65]

Answer:

Fundamentally, chemistry is the study of matter and change. The way that chemists study matter and change and the types of systems that are studied varies dramatically. Traditionally, chemistry has been broken into five main subdisciplines: Organic, Analytical, Physical, Inorganic, and Biochemistry.

hope this helps :)

5 0
3 years ago
CH4 + 202 → CO2 + 2H2O
ohaa [14]
It’s a combustion reaction but what are you trying to find?
6 0
2 years ago
What quantity measures the amount of space an object occupies?
mylen [45]
The answer would be volume
3 0
1 year ago
Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 7.9 g of methane is
Vikki [24]

Explanation:

The given reaction is as follows.

     CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O

As it is known that number of moles equal mass divided by molar mass. Molar mass of methane is 16 g/mol.

Hence,   No. of moles = \frac{mass}{molar mass}

                                   = \frac{7.9 g}{16 g/mol}

                                   = 0.493 mol

Molar mass of oxygen is 32 g/mol.

Hence, its number of moles = \frac{mass}{molar mass}

                                            = \frac{14.4 g}{32 g/mol}

                                            = 0.45 mol

As, it is shown from the reaction that 1 mole of methane needs 2 mole of oxygen.

Therefore, 0.493 mol of methane needs 2 \times 0.45 mol equals 0.9 moles of oxygen.

As there is only 0.45 moles of oxygen for the reaction. So, it means that oxygen is the limiting reagent.

Hence, for 0.45 moles of oxygen, methane required is as follows.

                        \frac{0.45}{2} = 0.225 moles

So, 0.225 moles of methane is equal to 0.225 \times 16 = 3.6 g

As, 3.6 g of methane reacts with oxygen. Therefore, amount of methane remains is calculated as follows.

                   (7.9 g - 3.6 g) = 4.3 g

 Thus, we can conclude that the minimum mass of methane that could be left over by the chemical reaction is 4.3 g.

8 0
3 years ago
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