Answer:
Nothing seems incorrect to me I feel u are doing great keep up the outstanding work.^-^
Hoped I Have Helped Honey Have A Nice Day "Peace"
Step-by-step explanation:
121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range

The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.
The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:

So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range

That's probably the answer they're looking for.
Answer:
D
Step-by-step explanation:
last one
Thanks me later
Answer:
14 blocks
Step-by-step explanation: