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4 years ago

In an electric motor, a commutator

Physics

2 answers:

alexdok [17]4 years ago

4 0

Answer:

b. Repeatedly reverses the flow of current through the armature.

Explanation:

The electric motor is a device that converts the electrical energy into mechanical energy.
The commutator is a device that repeatedly reverses the flow of current through the armature.
It is a split ring that acts as the commutator.
It connects the external circuit through a carbon brush and the armature of the motor.
Another important component of an electric motor is an electromagnet or permanent magnet.

Monica [59]4 years ago

4 0

Answer:

b on edg 2020

Explanation:

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If it is 9 am in San Francisco, is it also 9 am in New York? Why or why not?

Sedaia [141]

Answer:

It wouldn't be 9am in New York because San Francisco is 3 hours behind of New York

Explanation:

7 0

3 years ago

an Olympic runner leaps over a hurdle.if the runner initial vertical speed is 2.2m/s how much will the runners center of mass be

Snowcat [4.5K]

Supposing the runner is condensed to a point and moves upward at 2.2 m/s.
It takes a time = 2.2/g = 2.2/9.8 = 0.22 seconds to increase to max height.
Now looking at this condition in opposite - that is the runner is at max height and drops back to earth in 0.22 s (symmetry of this kind of motion).
From what height does any object take 0.22 s to fall to earth (supposing there is no air friction)?
d = 1/2gt²= (0.5)(9.8)(0.22)²= 0.24 m

7 0

3 years ago

Mary is an avid game show fan and one of the contestants on a popular game show. She spins the wheel, and after 5.5 revolutions,

spin [16.1K]

Answer:

The angle is 23.2 radians, equivalent to 3.69 revolutions.

Explanation:

First, we need to find the angular acceleration of the wheel. This can be done using one of the kinematic formulas:

$\omega^{2}=\omega_0^{2}+2\alpha\theta\\\\\implies \alpha=\frac{\omega^{2}-\omega_0^{2}}{2\theta}$

Since the final angular velocity is zero after 5.5 revolutions (equivalent to 11π radians) we have that:

$\alpha=\frac{-(3.15rad/s)^{2}}{2(11\pi rad)}\\\\\alpha=-0.144rad/s^{2}$

Now, using the same equation, we can solve for the requested angle:

$\theta=\frac{\omega^{2}-\omega_0^{2}}{2\alpha}\\\\\theta=\frac{(1.80rad/s)^{2}-(3.15rad/s)^{2}}{2(-0.144rad/s^{2})}\\\\\theta=23.2rad$

Finally, it means that the angle through which the wheel has turned when the angular speed reaches 1.80 rad/s is 23.2 radians, equivalent to 3.69 revolutions.

8 0

3 years ago

A satellite is orbiting earth at a distance of 35.0 kilometers. The satellite has a mass of 500 kilograms. What is the force bet

Alika [10]

Answer:

F = 4856.32 N

Explanation:

Given,

A satellite is orbiting earth at a distance from Earth surface, h = 35000 m

The mass of the satellite, m = 500 Kg

The radius of the Earth, R = 6.371 x 10⁶ m

The mass of the Earth, M = 5.972 x 10²⁴ Kg

The gravitational constant, G = 6.67408 x 10 ⁻¹¹ m³ kg⁻¹ s⁻²

The force between the Earth and the satellite is given by the formula

F = GMm/(R+h)² N

Substituting the values in the above equation

F = (6.67408 x 10 ⁻¹¹ X 5.972 x 10²⁴ X 500) / (6.371 x 10⁶ + 35000)²

= 4856.32 N

Hence, the force between the planet and the satellite is, F = 4856.32 N

5 0

3 years ago

A particle moving in simple harmonic motion with a period T = 1.5 s passes through the equilibrium point at time t0 = 0 with a v

ch4aika [34]

Answer

given,

Time period= T = 1.5 s

If it's moving through equilibrium point at t₀= 0 with v = 1.0 m/s

v_max=1.00 m/s

we know,

v_ max=A ω

v = A sin (ωt)

-0.50= -1.00 sin (ωt)

sin (ωt) = 0.5

$\omega t = sin^{-1}(0.5)$

$\dfrac{2\pi}{T}\times t =0.524$

$\dfrac{2\pi}{1.5}\times t =0.524$

t = 0.125 s

we have time period T=1.5 it is the time to complete one oscillation

means from eq to right,then left,then eq,then left,then from right to eq

time taken for left = t/4 = 0.125/4 = 0.375 s

smallest value of time

=0.375 + 0.125

= 0.50 sec

7 0

3 years ago