The mechanical advantage of the pulley is 3.56
Explanation:
The Mechanical Advantage (MA) of a pulley system is given by
where
Load is the weight of the object lifted
Effort is the force applied in input
For the pulley in this problem, we have:
Effort = 55 N
While the load is the weight of the box of mass m = 20.0 kg:
Substittuing, we find the MA of the pulley:
#LearnwithBrainly
Answer:
.
Explanation:
The frequency of a wave is equal to the number of wave cycles that go through a point on its path in unit time (where "unit time" is typically equal to one second.)
The wave in this question travels at a speed of . In other words, the wave would have traveled
in each second. Consider a point on the path of this wave. If a peak was initially at that point, in one second that peak would be
How many wave cycles can fit into that ? The wavelength of this wave
gives the length of one wave cycle. Therefore:
.
That is: there are wave cycles in
of this wave.
On the other hand, Because that of this wave goes through that point in each second, that
wave cycles will go through that point in the same amount of time. Hence, the frequency of this wave would be
Because one wave cycle per second is equivalent to one Hertz, the frequency of this wave can be written as:
.
The calculations above can be expressed with the formula:
,
where
Answer:
d = (75 i ^ + 93 j ^ + 27 k ^) m , d2 = (900 i ^ + 1116 j ^ + 324 k ^) m
Explanation:
The two objects are in circular orbit together, therefore with the same angular velocity, after the launch they move with the relative velocity, so we can use the kinematic relation
v = d / t
d = v t
Reduce time to units SI
t = 5 min (60 s / 1 min) = 300 s
X axis
x = vₓ t
x = 0.25 300
x = 75 m
Y axis
y = t
y = 0.31 300
y = 93 m
Z axis
z= t
z = 0.09 300
z = 27 m
d = (75 i ^ + 93 j ^ + 27 k ^) m
For the time of 1 h
t2 = 1 h (3600s / 1 h) = 3600
x2 = 900 m
y2 = 1116 m
z2 = 324 m
d2 = (900 i ^ + 1116 j ^ + 324 k ^) m
Answer:
The value is
Explanation:
From the question we are told that
The dielectric constant is k = 1.5
The area of each plate is
The distance between the plates is
The charge on the capacitor is
Generally the electric field in a vacuum is mathematically represented as
Generally is the voltage of the capacitor which is mathematically represented as
Here is the capacitance of the capacitor in a vacuum which is mathematically represented as
Here is a constant with value
=>
=>
So
So
=>
The electric field when the dielectric slab is inserted is mathematically represented as
=>
=>
Generally the electric field between the plates is mathematically evaluated as
=>
=>
Generally the potential difference between the plates is
=>