3 years ago

What is the origin of a warm, wet air masses.

Physics

2 answers:

lukranit [14]3 years ago

8 0

The answer is D because it the tropical zone

Fofino [41]3 years ago

5 0

Answer:

An air mass acquires these characteristics above an area of land or water known as its source region. When the air mass sits over a region

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Vectors A and B lie in the xy-plane. Vector A has a magnitude of 19.1 and is at an angle of 125.5º counterclockwise from the +x-

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A mountaintop is a height y above the level ground. A woman measures the angle of elevation of the mountaintop to be θ when she

valentina_108 [34]

Let t = Theta and p = Phi
Tan t = y/x Then x =y/Tant.
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3 years ago

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3 years ago

A wheel decelerates from 13.5 rad s−1 to 6.0 rad s−1 in 7 s. Calculate the angular displacement

Igoryamba

Answer:

<em>Angular displacement=68.25 rad</em>

Explanation:

<u>Circular Motion</u>

If the angular speed varies from ωo to ωf in a time t, then the angular acceleration is given by:

$\displaystyle \alpha=\frac{\omega_f-\omega_o}{t}$

The angular displacement is given by:

$\displaystyle \theta=\omega_o.t+\frac{\alpha.t^2}{2}$

The wheel decelerates from ωo=13.5 rad/s to ωf=6 rad/s in t=7 s, thus:

$\displaystyle \alpha=\frac{6-13.5}{7}$

$\displaystyle \alpha=\frac{-7.5}{7}$

$\displaystyle \alpha=-1.071 \ rad/s^2$

Thus, the angular displacement is:

$\displaystyle \theta=13.5*7+\frac{-1.071*7^2}{2}$

$\displaystyle \theta=94.5-26.25$

$\boxed{\displaystyle \theta=68.25\ rad}$

Angular displacement=68.25 rad

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3 years ago