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makvit [3.9K]
4 years ago
13

How do carbon-12 and carbon-13 differ?

Physics
2 answers:
Romashka-Z-Leto [24]4 years ago
5 0

Answer:

They have different amounts of neutrons.  They have different mass numbers.

Leokris [45]4 years ago
4 0

They have different amount of neutrons

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What best describes the difference between the second sound wave and the first?
Vikki [24]
Missing an attached sheet with the sound waves. Please add the attached sheet so I can properly help.

Thanks! :D
8 0
3 years ago
A machine produces a larger force than you exert to operate the machine. How does this input distance of the machine compare to
arlik [135]

Answer:

Because the output force is greater than the input force, the input distance must be greater than the output distance.

Explanation:

7 0
3 years ago
When a wheel is rotated through an angle of 21◦ , a point on the circumference travels through an arc length of 2.1 m. When the
LiRa [457]

Answer:

R = 5.73 m

Explanation:

For an angle of rotation through 21 degree we know that

arc length is given as

angle \times Radius = Arc

now we know that

Arc = 2.1 m

Angle = 21 degree

Angle = 21\times \frac{\pi}{180}

so now we have

21\times \frac{\pi}{180} = \frac{2.1}{R}

R = \frac{2.1 \times 180}{21 \times \pi}

R = 5.73 m

6 0
3 years ago
In a real system of levers, wheels, or pulleys, the AMA is less than the IMA because _____.
pickupchik [31]
In a real system of levers, wheels, or pulleys, the AMA is less than the IMA because of friction. 
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5 0
3 years ago
Normal atmospheric pressure is 1.013 105 Pa. The approach of a storm causes the height of a mercury barometer to drop by 27.1 mm
Burka [1]

Answer:

The atmospheric pressure is 0.97622\times10^{5}\ Pa.

Explanation:

Given that,

Atmospheric pressure P_{atm}= 1.013\times10^{5}\ Pa    

drop height h'= 27.1 mm

Density of mercury \rho= 13.59 g/cm^3

We need to calculate the height

Using formula of pressure

p = \rho g h

Put the value into the formula

1.013\times10^{5}=13.59\times10^{3}\times9.8\times h

h =\dfrac{1.013\times10^{5}}{13.59\times10^{3}\times9.8}

h=0.76\ m

We need to calculate the new height

h''=h - h'

h''=0.76-27.1\times10^{-3}

h''=0.76-0.027

h''=0.733\ m

We need to calculate the atmospheric pressure

Using formula of atmospheric pressure

P=\rho g h

Put the value into the formula

P= 13.59\times10^{3}\times9.8\times0.733

P=0.97622\times10^{5}\ Pa

Hence, The atmospheric pressure is 0.97622\times10^{5}\ Pa.

7 0
3 years ago
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