Answer:
<em>Moment of inertia of the flywheel is equal to 10.19 kg-m^2</em>
<em></em>
Explanation:
The maximum rotational energy to be stored by the flywheel
= 2.00 x 10^6 J
Angular speed with which to store this energy ω = 443 rad/s
moment of inertia of the flywheel
= ?
Recall that the energy of a rotating body is gotten from the equation

Where
is the rotational energy of the rotating body
= moment of inertia of the body
ω = angular speed of the rotating body
imputing the values into the equation, we'll have
2.00 x 10^6 =
x 
2.00 x 10^6 =
x 196249
= (2.00 x 10^6) ÷ 196249 = <em>10.19 kg-m^2</em>