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4 years ago

What happens to the dependent variable in a controlled experiment?

2 answers:

4 0

A dependent variable is what is measured affected in the experiment.

Hope this helps!
(a brainliest would be appreciated)

timurjin [86]4 years ago

3 0

It will be affected with the data

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You leave a 3kW heater on in your room. You put it on at 8am and leave it on until 4pm. If a unit (1kWh) costs 12.5p, how much w

natali 33 [55]

Answer:

bpc

Explanation:

8 0

3 years ago

Which of the angles shown in this picture is the angle of incidence?<br> A<br> B

Dmitry_Shevchenko [17]

The pictures are not attached, therefore, I cannot give a specific choice.
However, I will try to help you out.

The angle of incidence is defined as the angle formed between the ray of light and the normal to the surface that the ray is falling on.

The angle of incidence can be shown in the attached image.

Therefore, for your question, choose the image on which the above description applies.

Hope this helps :)

6 0

3 years ago

Read 2 more answers

A Decay Chain

Strike441 [17]

Answer : The energy released in first step of thorium-232 decay chain is $7.974\times 10^{-13}J$

Explanation :

First we have to calculate the mass defect $(\Delta m)$ .

The balanced reaction is,

$^{232}Th\rightarrow ^{228}Ra+^{4}He$

Mass defect = Sum of mass of product - sum of mass of reactants

$\Delta m=(\text{Mass of Ra}+\text{Mass of He})-(\text{Mass of Th})$

$\Delta m=(228.0301069+4.002602)-(232.038054)=5.34\times 10^{-3}amu=8.86\times 10^{-30}kg$

conversion used : $(1amu=1.66\times 10^{-27}kg)$

Now we have to calculate the energy released.

$Energy=\Delta m\times (c)^2$

$Energy=(8.86\times 10^{-30}kg)\times (3\times 10^8m/s)^2$

$Energy=7.974\times 10^{-13}J$

The energy released is $7.974\times 10^{-13}J$

Therefore, the energy released in first step of thorium-232 decay chain is $7.974\times 10^{-13}J$

7 0

3 years ago

When you start the simulation, there is no friction and no air resistance ("Air Drag"). Apply full force to the right, 200N. Wil

kakasveta [241]

Answer:Like friction, the drag force always opposes the motion of an object. ... The drag coefficient can depend upon velocity, but we will assume that it is a ... At highway speeds, over 50% of the power of a car is used to overcome air drag. ... A zero net force means that there is no acceleration, as given by Newton's second law.

3 0

3 years ago

A car driving down the road speeds up to pass bus. While passing changed velocity from 10 m/s to 35 m/s in 5 seconds. What is th

VMariaS [17]

Answer:

The ans is 3

Explanation:

First write the given values and write the formula of acceleration than do velocity - final velocity by time taken is 10-35%5 so, therefore acceleration of car is 3

5 0

3 years ago