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AlexFokin [52]
3 years ago
15

1) What would the average acceleration be for a car at a stoplight that speeds up to 20 m/s in 10 seconds (in m/s^2)

Physics
2 answers:
Alexxx [7]3 years ago
7 0
1.)
Velocity is in m/s, and acceleration is in m/s^2 like you said. Because of this, we can calculate this by dividing the speed by the time it took to get to that speed.
(20 meters/second) / 10 seconds = 2 meters/ second^2

2.)
Same thing with the first one.
(100 meters/second) / 4 seconds = 25 meters / seconds^2
Olegator [25]3 years ago
3 0

Answer:

Part a)

a = 2 m/s/s

Part b)

a = - 25 m/s/s

Explanation:

As we know that the average acceleration id defined as the rate of change in the velocity of the object

so here it is given by formula

a = \frac{v_f - v_i}{\Delta t}

now we know that

v_f = 20 m/s

v_i = 0

\Delta t = 10 s

now we have

a = \frac{20 - 0}{10} = 2 m/s^2

Part b)

here car is travelling with speed 100 m/s

now driver slams brakes and car finally stop in t = 4 s

so the average acceleration is given as

a = \frac{v_f - v_i}{\Delta t}

now we know that

v_f = 0 m/s

v_i = 100

\Delta t = 4 s

now we have

a = \frac{0 - 100}{4} = -25 m/s^2

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A sound wave traveling at STP has a period of .0023 seconds. The wavelength of this sound is closest to
agasfer [191]

Answer: 3

Wavelength = 0.76m

Explanation:

When sound wave is travelling at standard temperature and pressure ( STP), its speed will be equal to normal speed of sound which is equal to 331 m/s

Given that the period of the wave is 0.0023 seconds.

Wave speed = wavelength/period

Substitute the wave speed and the period to obtain wavelength

331 = wavelength/0.0023

Cross multiply

Wavelength = 331 × 0.0023

Wavelength = 0.7613 metre

The wavelength of this sound is closest to 0.76 m

4 0
4 years ago
An electric field with a magnitude of 6.0 × 104 N/C is directed parallel to the positive y axis. A particle with a charge q = 4.
jekas [21]

Answer:

Electric force, F=2.88\times 10^{-14}\ N

Explanation:

It is given that,

Magnitude of electric field, E=6\times 10^4\ N/C

Charge, q=4.8\times 10^{-19}\ C

The electric field is directed parallel to the positive y axis. We need to find the  force on the charge particle. It is given by :

F=q\times E

F=4.8\times 10^{-19}\ C\times 6\times 10^4\ N/C

F=2.88\times 10^{-14}\ N

So, the electric force on the charge is 2.88\times 10^{-14}\ N. Hence, this is the required solution.

5 0
4 years ago
B. In the vicinity of Earth’s orbit around the Sun, the energy intensity of sunlight is about 1600 W/m2 . What is the approximat
Vera_Pavlovna [14]

Answer:

1097.8 V/m

Explanation:

The equation that relates the intensity of an electromagnetic wave with the magnitude of the electric field is:

I=\frac{1}{2}c\epsilon_0 E^2

where

c is the speed of light

\epsilon_0 is the vacuum permittivity

E is the peak magnitude of the electric field

In this problem, we know the intensity:

I = 1600 W/m^2

So we can rearrange the formula to find E:

E=\sqrt{\frac{2I}{c\epsilon_0}}=\sqrt{\frac{2(1600 W/m^2)}{(3\cdot 10^8 m/s)(8.85\cdot 10^{-12} F/m)}}=1097.8 V/m

4 0
3 years ago
Consider the following mass distribution where the x- and y-coordinates are given in meters: 5.0 kg at (0.0, 0.0) m, 2.9 kg at (
Sauron [17]

Answer:

x = -1.20 m

y = -1.12 m

Explanation:

as we know that four masses and their position is given as

5.0 kg (0, 0)

2.9 kg (0, 3.2)

4 kg (2.5, 0)

8.3 kg (x, y)

As we know that the formula of center of gravity is given as

x_{cm} = \frac{m_1 x_1 + m_2x_2 + m_3x_3 + m_4x_4}{m_1 + m_2 + m_3 + m_4}

0 = \frac{5(0) + 2.9(0) + 4(2.5) + 8.3 x}{5 + 2.9 + 4 + 8.3}

10 + 8.3 x = 0

x = -1.20 m

Similarly for y direction we have

y_{cm} = \frac{m_1 y_1 + m_2y_2 + m_3y_3 + m_4y_4}{m_1 + m_2 + m_3 + m_4}

0 = \frac{5(0) + 2.9(3.2) + 4(0) + 8.3 y}{5 + 2.9 + 4 + 8.3}

9.28 + 8.3 x = 0

x = -1.12 m

5 0
3 years ago
If you have 4 kg of a sample with density of 1 897 g/ml what is the volume
Kaylis [27]
We know, Volume = Mass / Density
Here, mass = 4 Kg = 4000 g
d = 1,897 g/ml

Substitute their values, 
v = 4000 / 1897
v = 2.108 ml

In short, Your Answer would be 2.108 mL

Hope this helps!
3 0
3 years ago
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