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AlexFokin [52]
3 years ago
15

1) What would the average acceleration be for a car at a stoplight that speeds up to 20 m/s in 10 seconds (in m/s^2)

Physics
2 answers:
Alexxx [7]3 years ago
7 0
1.)
Velocity is in m/s, and acceleration is in m/s^2 like you said. Because of this, we can calculate this by dividing the speed by the time it took to get to that speed.
(20 meters/second) / 10 seconds = 2 meters/ second^2

2.)
Same thing with the first one.
(100 meters/second) / 4 seconds = 25 meters / seconds^2
Olegator [25]3 years ago
3 0

Answer:

Part a)

a = 2 m/s/s

Part b)

a = - 25 m/s/s

Explanation:

As we know that the average acceleration id defined as the rate of change in the velocity of the object

so here it is given by formula

a = \frac{v_f - v_i}{\Delta t}

now we know that

v_f = 20 m/s

v_i = 0

\Delta t = 10 s

now we have

a = \frac{20 - 0}{10} = 2 m/s^2

Part b)

here car is travelling with speed 100 m/s

now driver slams brakes and car finally stop in t = 4 s

so the average acceleration is given as

a = \frac{v_f - v_i}{\Delta t}

now we know that

v_f = 0 m/s

v_i = 100

\Delta t = 4 s

now we have

a = \frac{0 - 100}{4} = -25 m/s^2

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A.) If its booster rockets accelerate the space shuttle at 15m/s2, how high will it be one minute after launch?
poizon [28]

Answer:

27,000 m

450 m/s

Explanation:

Assuming the initial velocity is 0 m/s:

v₀ = 0 m/s

a = 15 m/s²

t = 60 s

A) Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (60 s) + ½ (15 m/s²) (60 s)²

Δy = 27,000 m

B) Find: v_avg

v_avg = Δy / t

v_avg = 27,000 m / 60 s

v_avg = 450 m/s

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Astronomers announced in August 2016 that they may have found such a planet orbiting Proxima Centauri. The newfound world, known as Proxima b, is about 1.3 times more massive than Earth, which suggests that the exoplanet is a rocky world, researchers said. The planet is also in the star's habitable zone, just 4.7 million miles (7.5 million kilometers) from its host star. It completes one orbit every 11.2 Earth-days. As a result, it's likely that the exoplanet is tidally locked, meaning it always shows the same face to its host star, just as the moon shows only one face (the near side) to Earth.



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In 2014, Kepler astronomers (including Matthews’ former student Jason Rowe) unveiled a “verification by multiplicity” method that should increase the rate at which astronomers promote candidate planets to confirmed planets. The technique is based on orbital stability — many transits of a star occurring with short periods can only be due to planets in small orbits, since multiply eclipsing stars that might mimic would gravitationally eject each other from the system in just a few million years.

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