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2 years ago

When I throw a ball in the air at what point will it have the least kinetic energy

2 answers:

7 0

When you throw the ball in the air it is considered kinetic energy. Once the ball reaches its max height, it stops moving and all kinetic energy turns into potential energy. So when the ball is at its highest point.

vfiekz [6]2 years ago

5 0

It will have the least kinetic energy when it is about to fall back dow after you throw it up in the air

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what is the magnitude of a force?(1 point) responses the motion of the force the motion of the force the direction of the force

mel-nik [20]

The term "unbalanced force" in Newton's first law refers to a force that is not entirely counterbalanced (or cancelled) by the other independent forces. Basically, magnitude can be thought of as simply the "value" or "amount" of any physical quantity. It is a scalar quantity at all times.

Force has both a magnitude and a direction because it is a vector quantity. The amount that encapsulates the force's strength is known as its magnitude.

Consider the following scenario: the force is 10 N in the east. The direction is indicated by "towards east," while the force is indicated by "10."

Unless acted upon by an unbalanced force, an object at rest tends to stay at rest, and an object in motion tends to stay in motion with the same speed and direction.

The term "unbalanced force" in Newton's first law refers to a force that is not entirely counterbalanced (or cancelled) by the other independent forces. An uneven force exists if either all the vertical forces (up and down) or all the horizontal forces do not cancel each other. Looking at the free-body diagram for a particular situation makes it easy to recognize whether an unbalanced force is present.

To know more about unbalanced force click on the link:

brainly.com/question/19054208

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6 0

9 months ago

Jet aircraft maintenance crews are required to wear protective earplugs. Members of a particular crew wear earplugs that reduce

Taya2010 [7]

Answer:

So the sound intensity level they would experience without the earplugs is 110.32dB.

Explanation:

Given data

Sound intensity by factor =215

Sound intensity level =87 dB

To find

Sound intensity level they would experience without the earplugs

Solution

First we need to find the new sound intensity level

$I_{n}=215(10^{\frac{87}{10} } )\\I_{n}=1.08*10^{11})$

The dB can be calculated as:

$dB=10log(I_{n})\\$

Substitute the given values

$dB=10log(1.08*10^{11})\\dB=110.32dB$

So the sound intensity level they would experience without the earplugs is 110.32dB.

7 0

2 years ago

A camper walks away from camp. He walks 23.72m north, then 39.25m south and

Arte-miy333 [17]

Answer:

89.53 North

Explanation:

Total N-S displacement

23.72 - 39.25 + 105.06 = + 89.53

5 0

1 year ago

You are standing next to a table and looking down on a record player sitting on the table. Take the spindle (axis of rotation) t

VLD [36.1K]

Answer:

a) the rotational speed of the clay is 3.45 rad/s

b) the value of A in the equation of motion is 0.15 m

c) the value of ϕi is 90° or π/2 rad.

Explanation:

Given that;

Revolution per minute rpm = 33( 1/3) = 100/3

The frequency f = 100 / 3(60) = 0.55 Hz

Rotational speed W = 2πf

we substitute

W = 2π × 0.55

W = 3.45 rad/s

Therefore, the rotational speed of the clay is 3.45 rad/s

given equation; y(t)=Asin(ωt+ϕi)

given that radius = 0.15 m

y(t)=(0.2)sin(ωt+ϕi)

Therefore, the value of A in the equation of motion is 0.15 m

since y(t) has the maximum value at t =0

so at t=0

y(0) = (0.15)sin(ω(0)+ϕi)

= 0.15sin(ϕi)

this will give maximum value when ϕi = 90°

y(0) = (0.15)sin(ω(0)+ϕi)

= 0.15sin(90°)

= 0.15

hence, the value of ϕi is 90° or π/2 rad.

7 0

2 years ago

The photeselestric effect is observed when light of a sufficiently high frequency is focused onto a polished metal surface, emit

Helga [31]

Answer:

$3.4\cdot 10^{-19} J$

Explanation:

In order to convert the work function of cesium from electronvolts to Joules, we must use the following conversion factor:

$1 eV = 1.6 \cdot 10^{-19} J$

In our problem, the work function of cesium is

$E=2.1 eV$

so, we can convert it into Joules by using the following proportion:

$1 eV : 1.6\cdot 10^{-19} J = 2.1 eV : x\\x=\frac{(1.6\cdot 10^{-19} J)(2.1 eV)}{1 eV}=3.4\cdot 10^{-19} J$

8 0

2 years ago