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Ad libitum [116K]
3 years ago
7

According to the kinetic theory of gas particles, when do gas particles have some type of force between them?

Physics
2 answers:
VladimirAG [237]3 years ago
6 0
When the gas particles collide! Hope this helps.
Morgarella [4.7K]3 years ago
4 0
The second one is the answer
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A 7300 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.20 m/s2 and feels no appreci
Simora [160]

Answer:

Explanation:

We shall first calculate the velocity at height h = 575 m .

acceleration a = 2.2 m /s²

v² = u² + 2 a s

u is initial velocity , v is final velocity , s is height achieved

v² = 0 + 2 x 2.2 x 575

v = 50.3 m /s

After 575 m , rocket moves under free fall so g will act on it downwards

If it travels further by height H

from the relation

v² = u² - 2 g H

v = 0 , u = 50.3 m /s

H = ?

0 = 50.3² - 2 x 9.8 H

H = 129.08 m

Total height attained by rocket

= 575 + 129.08

= 704.08 m .

4 0
2 years ago
A car travels a distance of 98 meters in 10 seconds. What is the average speed of the car?
stira [4]

Answer:

C

Explanation:

4 0
3 years ago
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please hurry In which state of matter has the LEAST kinetic energy? A) gas B) liquid C) plasma D) solid
anastassius [24]
Molecules in the solid phase have the least amount of energy, while gas particles have the greatest amount of energy.
7 0
3 years ago
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Which of the following is true of our current knowledge of electrons?
frosja888 [35]
They have a negative charge and rotate around the nucleus
8 0
3 years ago
a) What is the average useful power output of a person who does6.00×10^6Jof useful work in 8.00 h? (b) Working at this rate, how
NARA [144]

Answer:

208.33 W

141.26626 seconds

Explanation:

E = Energy = 6\times 10^6\ J

t = Time taken = 8 h

m = Mass = 2000 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Height of platform = 1.5 m

Power is obtained when we divide energy by time

P=\frac{E}{t}\\\Rightarrow P=\frac{6\times 10^6}{8\times 60\times 60}\\\Rightarrow P=208.33\ W

The average useful power output of the person is 208.33 W

The energy in the next part would be the potential energy

The time taken would be

t=\frac{E}{P}\\\Rightarrow t=\frac{mgh}{208.33}\\\Rightarrow t=\frac{2000\times 9.81\times 1.5}{208.33}\\\Rightarrow t=141.26626\ s

The time taken to lift the load is 141.26626 seconds

5 0
3 years ago
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