Answer:
A) t = 22.5 min and B) t = 29.94 min
Explanation:
Initial concentration, [A]₀ = 100
Final concentration = 100 -75 = 25
Time = 45 min
A) First order reaction
ln[A] − ln[A]₀ = −kt
Solving for k;
ln[25] − ln[100] = - 45k
-1.386 = -45k
k = 0.0308 min-1
How long after its start will the reaction be 50% complete?
Initial concentration, [A]₀ = 100
Final concentration, [A] = 100 -50 = 50
Time = ?
ln[A] − ln[A]₀ = −kt
Solving for k;
ln[50] − ln[100] = - 0.0308 * t
-0.693 = -0.0308 * t
t = 22.5 min
B) Zero Order
[A] = [A]₀ − kt
Using the values from the initial reaction and solving for k, we have;
25 = 100 - k(45)
-75 = -45k
k = 1.67 M min-1
How long after its start will the reaction be 50% complete?
Initial concentration, [A]₀ = 100
Final concentration, [A] = 100 -50 = 50
Time = ?
[A] = [A]₀ − kt
50 = 100 - (1.67)t
-50 = - 1.67t
t = 29.94 min
T<span>he Formula for sodium chlorate is- </span>NaClO3.
Answer:
42.3moles
Explanation:
The chemical equation given in this question is as follows:
H2 + O2 → H2O
However, this equation is unbalanced, the balanced chemical equation is as follows:
2H2 + O2 → 2H2O
This equation shows that;
2 moles of hydrogen gas (H2) will produce 2 moles of water (H2O)
Hence, If 42.3 moles of water (H2O) are produced, 42.3 × 2/2
= 42.3moles of hydrogen was reacted.
C+O2=CO2. The 2 would be smaller than the chemical symbol. Hope this helped
