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ruslelena [56]
3 years ago
10

In an experiment, having too many variables

Chemistry
2 answers:
TEA [102]3 years ago
7 0
C will cause too many problems
zlopas [31]3 years ago
3 0

Answer: Having too many varibles will cause to many problems.

Explanation:

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A student is asked to determine the molarity of a strong base by titrating it with 0.250 M solution of H2SO4. The students is in
tamaranim1 [39]

Answer:

The molarity of the strong base is 0.625 M

Which procedural error will result in a strong base molarity that is too high?

⇒ Using a buret with a tip filled with air rather than the H2SO4 solution

Explanation:

<u>Step 1:</u> Data given

Molarity of H2SO4 = 0.250 M

The initial buret reading is 5.00 mL

The final reading is 30.00 mL

<u />

<u>Step 2:</u> Calculate volume of H2SO4 used

30.00 mL - 5.00 mL = 25.00 mL

<u>Step 3:</u> Calculate moles of H2SO4

0.250 M = 0.250 mol/L

Since there are 2 H+ ions per H2SO4

0.250 mol/L  * 2 = 0.500 mol/L

The number of moles H2SO4 = 0.500 mol/L * 0.025 L

Number of moles H2SO4 = 0.0125 mol

<u>Step 4</u>: Calculate moles of OH-

For 1 mol H2SO4, we need 1 mol of OH-

For 0.0125 mol of H2SO4, we have 0.0125 mol of OH-

<u>Step 5</u>: Calculate the molarity of the strong base

Molarity = moles / volume

Molarity OH- = 0.0125 mol / 0.02 L

Molarity OH - = 0.625 M

Which procedural error will result in a strong base molarity that is too high?

⇒ Using a buret with a tip filled with air rather than the H2SO4 solution

   

5 0
3 years ago
Complete the sentence. A substance that is more basic has a___pH
alex41 [277]

Answer:

Higher

Explanation:

6 0
3 years ago
Chemistry Question, Don't really know how to do it lol.
Scilla [17]

Answer: 17.2 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}

\text{Moles of} HgS=\frac{20.0 g}{233g/mol}=0.085moles

The balanced chemical equation is:

4HgS(s)+4CaO(s)\rightarrow 4Hg(l)+3CaS(s))+CaSO_4(s)  

According to stoichiometry :  

4 moles of HgS produce =  4 moles of Hg

Thus 0.085 moles of HgS will require=\frac{4}{4}\times 0.085=0.085moles  of Hg

Mass of Hg=moles\times {\text {Molar mass}}=0.085moles\times 200.6g/mol=17.2g

Thus 17.2 g of Hg will be produced form 20.0 g of HgS.

3 0
3 years ago
What is radioactivity​
Mumz [18]

Answer:

Radioactive decay is the process by which an unstable atomic nucleus loses energy by radiation. A material containing unstable nuclei is considered radioactive. Three of the most common types of decay are alpha decay, beta decay, and gamma decay, all of which involve emitting one or more particles or photons.

7 0
3 years ago
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How do I do oxidation numbers<br>​
Rom4ik [11]

Answer:

Oompf

Explanation:

5 0
3 years ago
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