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mrs_skeptik [129]
3 years ago
6

♔♔Can water stay liquid below zero degrees Celsius?✞♡♡♡​

Chemistry
2 answers:
astra-53 [7]3 years ago
6 0

Answer:

Yes, water can stay liquid below zero degrees Celsius. There are a few ways in which this can happen. The freezing point of water drops below zero degrees Celsius as you apply pressure. When we apply pressure to a liquid, we force the molecules to get closer together.

Explanation:

Hope this helps you. Have a nice day.^_^

Please mark as brainliest. It helps a lot:)

kipiarov [429]3 years ago
6 0

Answer:

yes water can stay liquid below 0 ° Celsius

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wel

Answer:

The answer would be 1.5 kJ.

Explanation:

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4 0
3 years ago
Nitroglycerin (c3h5n3o9) is a powerful explosive. its decomposition may be represented by 4c3h5n3o9 → 6n2 12co2 10h2o o2 this re
professor190 [17]
The balanced chemical reaction describing this decomposition is as follows:
<span>4c3h5n3o9 .............> 6N2 + 12CO2 +10H2O + O2

From the periodic table:
mass of oxygen = 16 grams
mass of nitrogen = 14 grams
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Therefore:
mass of </span><span>C3H5N3O9 = 3(12) + 5(1) + 3(14) + 9(16) = 227 grams
mass of O2 = 2(16) = 32 grams

From the balanced chemical equation:
4(227) = 908 grams of </span>C3H5N3O9 produce 32 grams of O2. Therefore, to know the amount of oxygen produced from 4.5*10^2 grams <span>C3H5N3O9, all we need to do is cross multiplication as follows:
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7 0
3 years ago
Read 2 more answers
5. A sample of pure acetyl salicylic acid had a mass of 0.268 grams. It was dissolved in NaOH and diluted to 500.00mL in a volum
Elza [17]

Answer:

a. 5.36x10⁻⁴ g/mL

b. 4.29x10⁻⁵ g/mL

Explanation:

As the units for concentration are not specified, I'll respond using g/mL.

a. We <em>divide the sample mass by the final volume</em> in order to <u>calculate the concentration</u>:

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b. We can use C₁V₁=C₂V₂ for this question:

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3 years ago
suppose the burner under the pan of boiling water is turned to a higher settings. how will this affect the temperature of the wa
andrezito [222]

Answer:

Boiling hot?

Explanation:

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Answer:

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