Answer:
221 °C
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 4.1 L
Initial temperature (T₁) = 25 °C
= 25 °C + 273
= 298 K
Final volume (V₂) = 6.8 L
Final temperature (T₂) =?
The final temperature of the gas can be obtained as follow:
V₁ / T₁ = V₂ / T₂
4.1 / 298 = 6.8 / T₂
Cross multiply
4.1 × T₂ = 298 × 6.8
4.1 × T₂ = 2026.4
Divide both side by 4.1
T₂ = 2026.4 / 4.1
T₂ ≈ 494 K
Finally, we shall convert 494 K to celcius temperature. This can be obtained as follow:
°C = K – 273
K = 494
°C = 494 – 273
°C = 221 °C
Thus the final temperature of the gas is 221 °C
Answer:
2N2H2SO4
Explanation:
this is your answer calculate
Answer:
NH₃
Explanation:
mass H = 6.10 grams
mass N = 28.00 grams
mass cpd = (6.10 + 28.00)grams = 34.10 grams
%H/100wt = (6.10/34.10)100% = 17.9% w/w
%N/100wt = (28.00/34.1)100% = 82.1% w/w
%/100wt => grams/100wt => moles => ratio => reduce => emp ratio
%H/100wt = 17.9% w/w => 17.9g => (17.9/1)moles = 17.9 moles H
%N/100wt = 82.1% w/w => 82.1g => (82.1/14)moles = 5.9 moles N
Ratio N:H => 17.9 : 5.9
Reduce mole ratio (divide by smaller mole value) => 17.9/5.9 : 5.9/5.9
=> 3HY:1H empirical ratio => empirical formula NH₃ (ammonia)
Answer:
I'd say its speed but not to sure
Explanation:
Answer:
The bismuth sample.
Explanation:
The specific heat 
of a substance (might not be a metal) is the amount of heat required for heating a unit mass of this substance by unit temperature (e.g., 
.) The formula for specific heat is:
,
where
is the amount of heat supplied.
is the mass of the sample. 
is the increase in temperature.
In this question, the value of (amount of heat supplied to the metal) and (mass of the metal sample) are the same for all four metals. To find (change in temperature,) rearrange the equation:
,
.
In other words, the change in temperature of the sample, can be expressed as a fraction. Additionally, the specific heat of sample, , is in the denominator of that fraction. Hence, the value of the fraction would be the largest for sample with the smallest specific heat.
Make sure that all the specific heat values are in the same unit. Find the one with the smallest specific heat: bismuth (
.) That sample would have the greatest increase in temperature. Since all six samples started at the same temperature, the bismuth sample would also have the highest final temperature.
