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Nataly [62]
2 years ago
9

Which of the two types of synthetic polymer is more similar chemically to biopolymers? Explain.

Chemistry
1 answer:
loris [4]2 years ago
6 0

Natural polymer is more similar chemically to biopolymers.

Polymers are large molecules or high-molecular weight compounds formed from small repeating units. These repeating units are called monomer. Polymers are synthesized naturally and artificially. The number of repeating units in a chain is called the degree of polymerization.

There are two types of polymers:

1. Natural Polymers

2. Synthetic Polymers

Biopolymers are natural polymers produced by the cells of living organisms. Biopolymers consist of monomeric units that are covalently bonded to form larger molecules.

Synthetic polymers are the human-made polymers sometimes referred as plastics. The two major types of synthetic polymers are addition polymers and condensation polymers.

What are biopolymers?

Biopolymers polymer materials that form in living organisms. There are three main biopolymers in living systems; polysaccharides, proteins and polynucleotides (nucleic acids). The structural unit of polysaccharides is monosaccharides (sugars). When two monosaccharides join together to form a glycosidic bond, it releases a water molecule. Therefore, polysaccharides are condensation polymers. Polysaccharides play structural and functional roles in organisms. Glycogen is a storage polysaccharide, whereas cellulose is a component in the cell walls of plant cells. Glucose is the monomer for both glycogen and cellulose polymers.

Hence, we have conclude Biopolymers  are natural polymers produced by the cells of living organisms. Biopolymers consist of monomeric units that are covalently bonded to form larger molecules.

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Explanation:

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Ne4ueva [31]

Answer:

The Kc is 1.36 (but this is not an option, may be the options are wrong, or may be I was .. Thanks!)

Explanation:

Let's think all the situation.

               2 ICl(g)   ⇄   I₂(g)    +    Cl₂(g)

Initially      0.20              -               -

Initially I have only 0.20 moles of reactant, and nothing of products. In the reaction, an x amount of compound has reacted.

React          x              x/2               x/2

Because the ratio is 2:1, in the reaction I have the half of moles.

So in equilibrium I will have

           (0.20 - x)          x/2             x/2

Notice that I have the concentration in equilibrium so:

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So in equilibrium I have formed 0.14/2 moles of I₂ and H₂ (0.07 moles)

Finally, we have to make, the expression for Kc and remember that must to be with concentration in M (mol/L).

As we have a volume of 2L, the values must be /2

Kc = ([I₂]/2 . [H₂]/2) / ([ICl]/2)²

Kc = (0.07/2 . 0.07/2) / (0.060/2)²

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