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shutvik [7]
3 years ago
9

How do you find the molar mass for ba(NO3)2

Chemistry
1 answer:
Korvikt [17]3 years ago
8 0
To find the molar mass<span> of </span>Ba(NO3)2<span>, determine the </span>molar masses of all the atoms that form it. The Molar mass for Barium nitrate is <span>261.337 g/mol.</span>
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How many mmoles are in 8.34 mol ?
borishaifa [10]

Answer:

8.34 moles

Explanation:

We are given 8.34 moles.

We need to find moles: 8.34

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4 years ago
What is the biological significance of the temperature at which the amylase catalyzed reaction
ipn [44]

Answer:

The biological significance is that it is the normal human body temperature and also the optimum temperature of the enzyme.

Explanation:

  • Enzymes are biological catalysts that speed up the rate of chemical reactions.
  • Enzymes catalyze specific reactions by working on a specific substrate to convert it into a product.
  • The rate of enzyme activity depends on several factors which include pH, temperature, substrate concentration, and enzyme concentration among others.
  • Enzymes work best at a specific pH and temperature known as optimum pH and optimum temperature respectively.
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3 years ago
A reaction produces 0.809 moles of h2o. how many molecules are produced?
PSYCHO15rus [73]
Use Avogadro's number which is numerically equal to ...

( 6.02 multiply by 10 to the power of negative 23) 


Avocado's number is the number of particle(molecules, ions, atoms)  present in one mole of substance.

number of molecule in 0.809 mole of h20 = ....

one mole of h20 contains (6.02* 10^-23)

0.809 mole contains....(6.02* 10^-23) (0.809)
which is equal to [4.951* 10 ^-23]

if I made no mistake in calculation...it must be correct
3 0
3 years ago
Read 2 more answers
The distribution of Na+ ions across a typical biological membrane is 10 mmol dm-3 inside the cell and 140 mmol dm-3 outside the
trasher [3.6K]

Answer :  The value of \Delta G^o across the membrane is 6.80 kJ/mol

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln K_{eq}\\\\\Delta G^o=-RT\times \ln (\frac{C_{in}}{C_{out}})

where,

\Delta G^o = standard Gibbs free energy  = ?

R = gas constant = 8.314 J/K.mol

T = temperature = 37^oC=273+37=310K

K_{eq}  = equilibrium constant

C_{in} = concentration inside the cell = 10mmol.dm^{3-}

C_{out} = concentration outside the cell = 140mmol.dm^{3-}

Now put all the given values in the above formula, we get:

\Delta G^o=-RT\times \ln (\frac{C_{in}}{C_{out}})

\Delta G^o=-(8.314J/K.mol)\times (310K)\times \ln (\frac{10mmol.dm^{3-}}{140mmol.dm^{3-}})

\Delta G^o=6.80\times 10^{3}J/mol=6.80kJ/mol

Thus, the value of \Delta G^o across the membrane is 6.80 kJ/mol

8 0
3 years ago
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