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Trava [24]
3 years ago
12

What chemical change occurred in the following reaction? Mg2+(aq)+2OH−(aq)⟶ Mg(OH)2(s)

Chemistry
2 answers:
irina1246 [14]3 years ago
6 0
I think it might be a gas was formed.
Hope I'm right and it helps you out!!
7nadin3 [17]3 years ago
3 0

Answer : When magnesium salts combine with the alkaline water it induces precipitation of solid Mg(OH)_2.

Explanation :

  • Chemical change : The chemical change occurs when a substance combine with the another substance to form a new substance.

         It can not be easily reversible.

        The new product is formed or precipitate may be formed.

  • Physical change : The physical change occurs when a substance combine with the another substance then no new compound is formed.

        It can be reversible.

       No new product is formed only changes occurs in the state or                 phase.

As per question, when magnesium salts combine with the alkaline water it induces precipitation of solid Mg(OH)_2.

The balanced chemical reaction is,

Mg^{2+}(aq)+2OH^-(aq)\rightarrow Mg(OH)_2(s)

That mean a new compound is formed by this reaction. So, the chemical change occurred in this reaction.

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Sodium has the atomic number 11. How many electrons are in a sodium ion, which has the symbol Na+? 10 11 12 NextReset © 2017 Edm
Anna71 [15]
Na 1s²2s²2p⁶3s¹
↓ - e⁻
Na⁺ 1s²2s²2p⁶    2+2+6=10 e⁻

10 electrons are in sodium ion Na⁺
4 0
3 years ago
A fat is composed of long chains of carbon and hydrogen atoms. In a reaction with a strong base, a fat forms a soap and glycerol
Nonamiya [84]

Answer:

Empirical formula is C₉H₁₅O

Molecular formula = C₈₁H₁₃₅O ₉

Explanation:

Percentage of carbon = 77.60%

Percentage of oxygen = 11.45%

Percentage of hydrogen = 10.95%

Molecular weight = 1253 g/mol

Molecular formula = ?

Empirical formula = ?

Solution:

Number of gram atoms of C = 77.60 g /12g/mol =6.5

Number of gram atoms of O = 11.45 g / 16 g/mol = 0.72

Number of gram atoms of H = 10.95 g / 1.008 g/mol= 10.9

Atomic ratio:

C               :            H                 :    O

6.5/0.72   :       10.9/0.72         :   0.72/0.72

     9          :            15              :         1

C : H : O = 9 : 15 : 1

Empirical formula is C₉H₁₅O

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

n = 1253 / 139

n = 9

Molecular formula = n (empirical formula)

Molecular formula = 9 (C₉H₁₅O )

Molecular formula = C₈₁H₁₃₅O ₉

4 0
3 years ago
Out of 500 silicon atoms: 460 are si-28, which has a mass of 27.98 amu 25 are si-29, which has a mass of 28.98 amu and 15 are si
liberstina [14]

Answer;

=28.09 amu

Explanation;

In this problem, they did not give us the percentages. However, since we know the number of atoms, we can easily calculate the percentages. For example:  

(460 X 100)/500 = 92%  

If we do this for all three isotopes,

(460 × 25)/500 = 5 %

(460 × 15) /500 = 3%

-We get 92%, 5%, and 3%. (We'll assume these are absolute numbers for determining our significant figures).

Now the problem is just like the previous one. First convert the percentages into decimals. Then multiply those decimals by the masses and add. Here's the solution:  

= (0.92) X (27.98 amu) + (0.05) X (28.98 amu) + (0.03) X (29.97 amu)

= 25.74 amu  +  1.449 amu  + 0.8991 amu

= 28.09 amu

6 0
3 years ago
Read 2 more answers
2 A(g) + B(g) ---> 2 C(g)Rate = k [A][B]At the beginning of one trial of this reaction, [A] = 3.0 M and [B] = 1.0 M. The obse
Orlov [11]

Answer:

Lmol⁻¹s⁻¹

Explanation:

The rate law of the given reaction is:-

Rate=k[A][B]

Wherem, k is the rate constant.

Given that:-

Rate = 0.36 mol/Lsec = 0.36 M/sec

[A] = 3.0 M

[B] = 1.0 M

Thus,

Applying in the equation as:-

0.36 M/sec =k × 3.0 M× 1.0 M

k = 0.12 (Ms)⁻¹ = 0.12 Lmol⁻¹s⁻¹

<u>The units of k = Lmol⁻¹s⁻¹</u>

6 0
3 years ago
What is not produced during glycosis
a_sh-v [17]
The energy containing electron transporters of FADH2 are not produced during glycolysis.
4 0
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