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Alik [6]
2 years ago
13

What is the value of x in the figure below? In this diagram, △ABD~△CAD.

Mathematics
1 answer:
morpeh [17]2 years ago
7 0

<u>Given</u>:

Given that the triangles ABD and CAD are similar.

The length of AB is 12.

The length of BD is x.

The length of AC is 27.

We need to determine the value of x.

<u>Value of x:</u>

Let us use the leg rule to determine the value of x.

Thus, we have;

\frac{BC}{AB}=\frac{AB}{BD}

Substituting the values, we get;

\frac{27}{12}=\frac{12}{x}

Cross multiplying, we get;

27x=12\times 12

27x=144

Dividing both sides by 27, we have;

x=\frac{16}{3}

Thus, the value of x is \frac{16}{3}

Hence, Option D is the correct answer.

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Answer:
The probability the student studies Art and
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Step-by-step explanation:
Denote the events as follows:
A = a students studies Art
B= a students studies Biology
The information provided is:
N = 42
n (An B) = 9
n (A' n B) = 10
n (A' n B') =7
Then the number of students who study Art
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n(An B') = N -n (An B) -n (A' nB) - n (A'n B')
= 42 - 10 - 7 - 9
= 16
The number of students who study Art but
not Biology is 16.
Compute the probability the student studies
Art and Biology as follows:
P(ANB)
n(ANB)
= 0.2143
Thus, the probability the student studies Art
and Biology is 0.2143.
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