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Strike441 [17]
2 years ago
14

A climber is attached to a vertical rope that has a tension of

Physics
1 answer:
algol [13]2 years ago
7 0
That is tention in the butt hole?  /*\
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What is the effect of the author proposing a "thought experiment" at the beginning of the text? FINANCIAL LITERACY
mojhsa [17]

A thought experiment aims to promote speculative thinking, logical reasoning, and paradigm shifts. Thought experiments force us to address problems we find difficult to answer, which forces us out of our comfort zone. They highlight knowledge gaps and aid in recognizing the boundaries of what is knowable.

<h3>What are thought experiments?</h3>

Thought experiments are imaginative methods for examining the nature of things. They are employed for a variety of purposes in a number of disciplines, including physics, economics, history, mathematics, and philosophy.

A thought experiment is a test that we do in our minds. Here, we will imagine a specific scenario, consider some of its repercussions, and come to a broad conclusion.

Therefore, a thought experiment aims to promote speculative thinking, logical reasoning, and paradigm shifts. Thought experiments force us to address problems we find difficult to answer, which forces us out of our comfort zone. They highlight knowledge gaps and aid in recognizing the boundaries of what is knowable.

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4 0
1 year ago
Consider a one-dimensional crystal (similar to a carbon nanowire) with length 10 um and lattice spacing 0.1 nm.
Finger [1]

Answer:

a)  Fermi level = 600 electron-volts

b) \frac{2.04 * 10^{13} }{\sqrt{E} }

Explanation:

Given data:

length of one-dimensional crystal = 10 um

Lattice spacing = 0.1 nm

A) Determine the Fermi level assuming one electron per atom

Total length = 10 <em>u</em>m

Interatomic separation of a = 0.1 nm

in this case the Atom has one electron therefore the number of electrons = 10^5  and the number of states Ns = gsN = 2 * 10^5  ( attached below is some part of the solution )

hence : Fermi level = 600 electron-volts

B) Determine the density of states as a function of electron energy

attached below is the detailed solution

5 0
3 years ago
if you place 0°c ice into 0°c water in an insulated container, what will happen? Will some ice melt, will more water freeze, or
antoniya [11.8K]

Answer:

neither will happen

Explanation:

cause the water is already defreezed

6 0
2 years ago
if the user exerts a 14 n force on the upper handle, estimate the force on the clove. express your answer with the appropriate u
Marizza181 [45]

The force on the clove will have the same magnitude but a negative sign with it that is F = - 14 N

<h3>What is force and how do we calculate it ?</h3>

The definition of force is: The pushing or pulling on a massed object changes its velocity. Force is an external agent that has the power to alter a body's resting or moving condition.

It has a size and a movement.

Newton's second law of motion defines the force formula as follows:

A force is equal to an object's mass times its acceleration, or F = m a. You must use SI units when applying this formula: kilograms for mass, meters per second squared for acceleration, and newtons for force.

To know more about force you may visit the link which is :

brainly.com/question/26115859

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3 0
1 year ago
Where is the near point of an normal eye when accidentally wear a contact lens with a power of +2.0 diopters?
Lerok [7]

Answer:

The near point of an eye with power of +2 dopters, u' = - 50 cm

Given:

Power of a contact lens, P = +2.0 diopters

Solution:

To calculate the near point, we need to find the focal length of the lens which is given by:

Power, P = \frac{1}{f}

where

f = focal length

Thus

f = \frac{1}{P}

f = \frac{1}{2} = + 0.5 m

The near point of the eye is the point distant such that the image formed at this point can be seen clearly by the eye.

Now, by using lens maker formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{u'}

where

u = object distance = 25 cm = 0.25 m = near point of a normal eye

u' = image distance

Now,

\frac{1}{u'} = \frac{1}{f} - \frac{1}{u}

\frac{1}{u'} = \frac{1}{0.5} - \frac{1}{0.25}

\frac{1}{u'} = \frac{1}{f} - \frac{1}{u}

Solving the above eqn, we get:

u' = - 0.5 m = - 50 cm

7 0
2 years ago
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