A situation that involves the transfer of heat by means of convection must involve the exchange of fluid currents such as land and sea breezes.
Heat transfer by convection is a method of heat transfer by which heat is transferred between two bodies through through currents of moving fluids or gases.
The following are examples of heat transfer by convection;
- land breezes cooling the sea at night
- sea breezes cooling the land during the day
- boiling of water
- circulation of blood, etc
Thus, a situation that involves the transfer of heat by means of convection must involve the exchange of fluid currents such as land and sea breezes.
Learn more here:brainly.com/question/17394233
Answer:
<em>The sprinter traveled a distance of 7.5 m</em>
Explanation:
<u>Motion With Constant Acceleration
</u>
It's a type of motion in which the rate of change of the velocity of an object is constant.
The equation that rules the change of velocities is:
![v_f=v_o+at\qquad\qquad [1]](https://tex.z-dn.net/?f=v_f%3Dv_o%2Bat%5Cqquad%5Cqquad%20%5B1%5D)
Where:
a = acceleration
vo = initial speed
vf = final speed
t = time
The distance traveled by the object is given by:
![\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3Dv_o.t%2B%5Cfrac%7Ba.t%5E2%7D%7B2%7D%5Cqquad%5Cqquad%20%5B2%5D)
Using the equation [1] we can solve for a:
![\displaystyle a=\frac{v_f-v_o}{t}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20a%3D%5Cfrac%7Bv_f-v_o%7D%7Bt%7D)
The sprinter travels from rest (vo=0) to vf=7.5 m/s in t=2 s. Computing the acceleration:
![\displaystyle a=\frac{7.5-0}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20a%3D%5Cfrac%7B7.5-0%7D%7B2%7D)
![a=3.75\ m/s^2](https://tex.z-dn.net/?f=a%3D3.75%5C%20m%2Fs%5E2)
Now calculate the distance:
![\displaystyle x=0*2+\frac{3.75*2^2}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D0%2A2%2B%5Cfrac%7B3.75%2A2%5E2%7D%7B2%7D)
![\displaystyle x=7.5\ m](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D7.5%5C%20m)
The sprinter traveled a distance of 7.5 m
Answer:
<em>The divers pull in their limbs and curl up their bodies because</em> doing so decreases their moment of inertia and increases their angular velocity
Explanation:
<em>The conservation of angular momentum</em> states that in a rotational system, the initial angular momentum is equal to the final angular momentum if no torque acts on it.
Angular momentum is equal to the product of the moment of inertia about its axis and the angular velocity
Angular momentum = Iω![\\](https://tex.z-dn.net/?f=%5C%5C)
where I = moment of inertial = mass x ![radius^{2}](https://tex.z-dn.net/?f=radius%5E%7B2%7D)
I = m![r^{2}](https://tex.z-dn.net/?f=r%5E%7B2%7D)
angular momentum = m
ω
since angular momentum is constant, one can see that decreasing the radius of rotation about the body by curling in the limb will cause the moment of inertia to decrease and the angular velocity to increase.
NB: mass of the body is constant.
Because dogs have their bodies covered with fur, sweating is less effective. Dogs have sweat glads in places where there is little fur. However this is not enough in some hot days. To keep the body temperature in order dogs have to rely on panting. The interior of mouth and lungs is wet, so breathing quickly speeds up cooling. It acts similarly to wind blowing on sweaty person's skin.
You can try it on your own. When you breathe heavily you will feel coolness :)
In order to evaporate (change state from liquid to gas) heat energy has to be delivered to water. The heat energy is taken from the body of dog, thus cooling it.