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choli [55]
3 years ago
9

Which is the final event that occurs when a star is forming ​

Physics
1 answer:
KengaRu [80]3 years ago
5 0
Nuclear fusion begins under high pressure
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a train leaves a station heading east at 50 mph from that same station a car drives north at a speed of 30mph after 3 hours how
Alecsey [184]

Answer:

d = 175 miles

Explanation:

Train is moving towards East with constant speed of 50 mph

While car is moving at speed of 30 mph

so after t = 3 hours

the distance moved by the train is given as

d_1 = vt

d_1 = (50)(3) = 150 miles

at the same time the distance moved by the car is given as

d_2 = 30(3) = 90 miles

now we know that both car and train is moving perpendicular to each other

So the distance between them after t = 3 hours is given as

d= \sqrt{d_1^2 + d_2^2}

d = \sqrt{150^2 + 90^2}

d = 175 miles

8 0
3 years ago
3 small identical balls have charges -3×10^-12 ,8×10^-12 and 4×10^-12 find the charge​
Norma-Jean [14]

Answer:

  3×10^-12 C  

Explanation:

The total of the three charges is ...

   (-3 +8 +4)×10^-12 C = 9×10^-12 C

Assuming the charge is equally distributed between the balls when they are brought in contact, the charge on each ball will be ...

  (9/3)×10^-12 C = 3×10^-12 C

7 0
3 years ago
A solid sphere of weight 42.0 N rolls up an incline at an angle of 36.0°. At the bottom of the incline the center of mass of the
Alecsey [184]

Answer:

Part a)

KE = 77.95 J

Part b)

L = 3.16 m

Part c)

distance L is independent of the mass of the sphere

Explanation:

Part a)

As we know that rotational kinetic energy of the sphere is given as

KE = \frac{1}{2}I\omega_2 + \frac{1}{2}mv^2

so we will have

KE = \frac{1}{2}(\frac{2}{5}mR^2)(\frac{v}{R})^2 + \frac{1}{2}mv^2

so we will have

KE = \frac{1}{5} mv^2 + \frac{1}{2}mv^2

KE = \frac{7}{10} mv^2

KE = \frac{7}{10}(\frac{42}{9.81})(5.10^2)

KE = 77.95 J

Part b)

By mechanical energy conservation law we know that

Work done against gravity = initial kinetic energy of the sphere

So we will have

mgLsin\theta = KE

\frac{42}{9.81}(9.81)L sin36 = 77.95

L = 3.16 m

Part c)

by equation of energy conservation we know that

\frac{7}{10}mv^2 = mgL sin\theta

so here we can see that distance L is independent of the mass of the sphere

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3 years ago
PLEASE HELP WITH THIS QUESTION WILL GIVE BRAINLIST TO BEST ANSWER
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The net force is 12 N to the left.
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