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Arte-miy333 [17]
3 years ago
7

Prove that for a,b,c E ℤ, if a ❘ ( ab + c ), then a I c.

Mathematics
1 answer:
zhenek [66]3 years ago
3 0

Answer:

True.

Step-by-step explanation:

Let a,b,c integers  and a | (ab+c), that is to say that there exist a integer k such that ab+c = ka. Then:

ab+c = ka

c = ka-ab

c = a(k-b). So, c is a multiple of a, that is a | c.

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Mr. Brown chooses a fiction book at random from a list of books and then chooses a second fiction book from those remaining.
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Dependent would be when Mr.Brown then chooses a second fiction. book from those remaining.
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There are 48 people who have signed up to attend the midnight barbecue at the Rainbow Canyon Recreation Center. The chef wants t
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A) 264 11/2 *48
B) 66 pounds of beef needed .25*264
C) 66 pounds
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3 years ago
PLEASE HELP WITH ALL QUESTIONS WILL GIVE BRAINLIEST AND WILL GIVE 33 POINTS
MrMuchimi

uh where the question?

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3 years ago
If the original square had a side length of
irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas  in the attached figure N 3, and the trinomial is x^{2} +11x+28

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

Length=(x+4)\ in

width=(x+7)\ in

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas  in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

A1=(x)(x)=x^{2}\ in^2

A2=(4)(x)=4x\ in^2

A3=(x)(7)=7x\ in^2

A4=(4)(7)=28\ in^2

The total area of the second rectangle is the sum of the four areas

A=A1+A2+A3+A4

State the product of (x+4) and (x+7) as a trinomial

(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28

Part c) If the original square had a side length of  x = 2 inches, then what is the area of the  second rectangle?

we know that

The area of the second rectangle is equal to

A=A1+A2+A3+A4

For x=2 in

substitute the value of x in the area of each portion

A1=(2)(2)=4\ in^2

A2=(4)(2)=8\ in^2

A3=(2)(7)=14\ in^2

A4=(4)(7)=28\ in^2

A=4+8+14+28

A=54\ in^2

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

A(x)=x^{2} +11x+28

For x=2 in

substitute and solve for A(x)

A(2)=2^{2} +11(2)+28

A(2)=4 +22+28

A(2)=54\ in^2 ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0
4 years ago
Abi is carrying 3 gallons of milk. Each gallon of milk weighs 8.6 pounds. Abi wants to know the total weight of milk he is carry
Vesna [10]

Answer:

25.8 pounds

Step-by-step explanation:

3 x 8.6 = 25.8

6 0
3 years ago
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