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Arte-miy333 [17]
3 years ago
7

Prove that for a,b,c E ℤ, if a ❘ ( ab + c ), then a I c.

Mathematics
1 answer:
zhenek [66]3 years ago
3 0

Answer:

True.

Step-by-step explanation:

Let a,b,c integers  and a | (ab+c), that is to say that there exist a integer k such that ab+c = ka. Then:

ab+c = ka

c = ka-ab

c = a(k-b). So, c is a multiple of a, that is a | c.

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Which Greek geometer founded a philosophical society that developed its self to the study of mathematics
MA_775_DIABLO [31]

Pythagoras was the Greek Scholar that caused Mathematics

4 0
4 years ago
Which of the following describes the correct process for solving the equation 2x + 6 =22 and arrives at the correct solution
olga nikolaevna [1]

Answer:

Step-by-step explanation:

Starting with 2x+6=22

You subtract 6 from each side of the equation:

2x=16

You want to isolate the "x" so you divide each side by 2.

x = 8

check your answer: 2x + 6 = 22

2(8) + 6 = 22

16 + 6 = 22

3 0
3 years ago
What two numbers have a product of -2 and a sum of 7
Citrus2011 [14]

<em>Greetings from Brasil...</em>

According to the statement of the question, we can assemble the following system of equation:

X · Y = - 2      i

X + Y = 7       ii

isolating X from i and replacing in ii:

X · Y = - 2

X = - 2/Y

X + Y = 7

(- 2/Y) + Y = 7     <em>multiplying everything by Y</em>

(- 2Y/Y) + Y·Y = 7·Y

- 2 + Y² = 7X     <em> rearranging everything</em>

Y² - 7X - 2 = 0      <em>2nd degree equation</em>

Δ = b² - 4·a·c

Δ = (- 7)² - 4·1·(- 2)

Δ = 49 + 8

Δ = 57

X = (- b ± √Δ)/2a

X' = (- (- 7) ± √57)/2·1

X' = (7 + √57)/2

X' = (7 - √57)/2

So, the numbers are:

<h2>(7 + √57)/2</h2>

and

<h2>(7 - √57)/2</h2>
7 0
4 years ago
Find the volume of a cylinder that has a diameter of 6 and a height of 9. Leave your answer in terms of (pie)
laiz [17]

V = π x r² x h


V= π  x 6² x9

V= 324 π  


5 0
3 years ago
Read 2 more answers
What's the solution of the equation 4[x+2(3x-7)]=22x-65
padilas [110]

Answer:

x = -3/2

Step-by-step explanation:

Let's solve your equation step-by-step.

4(x+2(3x−7))=22x−65

Step 1: Simplify both sides of the equation.

4(x+2(3x−7))=22x−65

(4)(x)+(4)(2(3x−7))=22x+−65(Distribute)

4x+24x+−56=22x+−65

(4x+24x)+(−56)=22x−65(Combine Like Terms)

28x+−56=22x−65

28x−56=22x−65

Step 2: Subtract 22x from both sides.

28x−56−22x=22x−65−22x

6x−56=−65

Step 3: Add 56 to both sides.

6x−56+56=−65+56

6x=−9

Step 4: Divide both sides by 6.

6x = -9

6       6

x =  -3/2

8 0
3 years ago
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