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3 years ago

6

georges playground is shown in the diagram he wants to buy timber to put all around it so that mulch does not spread how much ti

mber does he need

1 answer:

Xelga [282]3 years ago

7 0

He needs 84 ft.
Step by step explanation:
(24*2)+(18*2)
48+36
84

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An art museum has a pentagon-shaped room. When drawn to scale on a coordinate grid, the corners of the room are points (18,20):

AURORKA [14]

Answer:

$2\ gal$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$A(18,20),B(4,20),C(4,4),D(16.2),E(22.10)$

step 1

Find the distance AB

we have

$A(18,20),B(4,20)$

substitute in the formula

$d=\sqrt{(20-20)^{2}+(4-18)^{2}}$

$d=\sqrt{(0)^{2}+(-14)^{2}}$

$AB=14\ ft$

step 2

Find the distance BC

we have

$B(4,20),C(4,4)$

substitute in the formula

$d=\sqrt{(4-20)^{2}+(4-4)^{2}}$

$d=\sqrt{(-16)^{2}+(0)^{2}}$

$BC=16\ ft$

step 3

Find the distance DE

we have

$D(16.2),E(22.10)$

substitute in the formula

$d=\sqrt{(10-2)^{2}+(22-16)^{2}}$

$d=\sqrt{(8)^{2}+(6)^{2}}$

$d=\sqrt{100}$

$DE=10\ ft$

step 4

Find the distance AE

we have

$A(18,20),E(22.10)$

substitute in the formula

$d=\sqrt{(10-20)^{2}+(22-18)^{2}}$

$d=\sqrt{(-10)^{2}+(4)^{2}}$

$d=\sqrt{116}$

$AE=10.77\ ft$

step 5

Find out the area of the four walls

To determine the area sum the length sides and multiply by the height of the walls

so

$A=(AB+BC+DE+AE)h$

substitute the given values

The height of the walls is 10 ft

$A=(14+16+10+10.77)10$

$A=(50.77)10$

$A=507.7\ ft^2$

step 6

Determine the number of gallons needed to paint the four walls

we know that

one gallon of paint is enough to cover 400 square feet

using proportion

$\frac{1}{400}\ \frac{gal}{ft^2}=\frac{x}{507.7}\ \frac{gal}{ft^2}\\\\x=507.7/400\\\\x= 1.27\ gal$

Round up

$x=2\ gal$

5 0

3 years ago

How do you write "the difference between twenty and a number and four is six" as an algebraic expression?

kicyunya [14]

Using the variable x for the unknown number,

20 - (x + 4) = 6

is your answer!
Hope I helped :)

5 0

3 years ago

Solve the system of the following equations:

schepotkina [342]

The answer is (5,-2)

4 0

2 years ago

Read 2 more answers

Please help? I’m super lost...

babunello [35]

Answer:

Step-by-step explanation:

In all of these problems, the key is to remember that you can undo a trig function by taking the inverse of that function. Watch and see.

a. $sin2\theta =-\frac{\sqrt{3} }{2}$

Take the inverse sin of both sides. When you do that, you are left with just 2theta on the left. That's why you do this.

$sin^{-1}(sin2\theta)=sin^{-1}(-\frac{\sqrt{3} }{2} )$

This simplifies to

$2\theta=sin^{-1}(-\frac{\sqrt{3} }{2} )$

We look to the unit circle to see which values of theta give us a sin of -square root of 3 over 2. Those are:

$2\theta =\frac{5\pi }{6}$ and

$2\theta=\frac{7\pi }{6}$

Divide both sides by 2 in both of those equations to get that values of theta are:

$\theta=\frac{5\pi }{12},\frac{7\pi }{12}$

b. $tan(7a)=1$

Take the inverse tangent of both sides:

$tan^{-1}(tan(7a))=tan^{-1}(1)$

Taking the inverse tangent of the tangent on the left leaves us with just 7a. This simplifies to

$7a=tan^{-1}(1)$

We look to the unit circle to find which values of <em>a</em> give us a tangent of 1. They are:

$7\alpha =\frac{5\pi }{4},7\alpha =\frac{\pi }{4}$

Dibide each of those equations by 7 to find that the values of alpha are:

$\alpha =\frac{5\pi}{28},\frac{\pi}{28}$

c. $cos(3\beta)=\frac{1}{2}$

Take the inverse cosine of each side. The inverse cosine and cosine undo each other, leaving us with just 3beta on the left, just like in the previous problems. That simplifies to:

$3\beta=cos^{-1}(\frac{1}{2})$

We look to the unit circle to find the values of beta that give us the cosine of 1/2 and those are:

$3\beta =\frac{\pi}{6},3\beta =\frac{5\pi}{6}$

Divide each of those by 3 to find the values of beta are:

$\beta =\frac{\pi }{18} ,\frac{5\pi}{18}$

d. $sec3\alpha =-2$

Let's rewrite this in terms of a trig ratio that we are a bit more familiar with:

$\frac{1}{cos(3\alpha) } =\frac{-2}{1}$

We are going to simplify this even further by flipping both fraction upside down to make it easier to solve:

$cos(3\alpha)=-\frac{1}{2}$

Now we will take the inverse cos of each side (same as above):

$3\alpha =cos^{-1}(-\frac{1}{2} )$

We look to the unit circle one last time to find the values of alpha that give us a cosine of -1/2:

$3\alpha =\frac{7\pi}{6},3\alpha =\frac{11\pi}{6}$

Dividing both of those equations by 3 gives us

$\alpha =\frac{7\pi}{18},\frac{11\pi}{18}$

And we're done!!!

8 0

2 years ago

The distance around the school track is 0.25 mile. It takes Maribeth 5.1 minutes to run 2 laps around the school track. At that

BabaBlast [244]

Answer:

10.2 minutes

Step-by-step explanation:

1 lap= 1/4 mile

2 laos= 1/2 mile

5.1 x 2= 10.2 minutes

7 0

2 years ago