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Aleonysh [2.5K]
3 years ago
7

how many moles of water are in 1.23 x 10^18 water molecules? I need the answer in scientific notation ?

Chemistry
1 answer:
Ann [662]3 years ago
8 0

Answer:

Moles=2.04×10^(-6)

Explanation:

No. Of moles=no. Of particles/ Avogadro's no

(Where no. Of particles may be atoms molecules or compounds)

Moles=1.23×10^18/6.022×10^23

Moles=0.204×10^(-5)

Moles=2.04×10^(-6)

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How many moles are 3.20 x102 formula units of calcium iodide?
DedPeter [7]

The number of moles in 3.20 x 10² formula units of calcium iodide is 0.053 moles.

<h3>How to calculate number of moles?</h3>

The number of moles in the formula units of a substance is calculated by dividing the formula unit by Avogadro's number.

According to this question, 3.20 x 10² formula units are in calcium iodide. The number of moles is as follows:

no of moles = 3.20 x 10²² ÷ 6.02 × 10²³

no of moles = 0.53 × 10-¹

no of moles = 0.053 moles

Therefore, the number of moles in 3.20 x 10² formula units of calcium iodide is 0.053 moles.

Learn more about number of moles at: brainly.com/question/12513822

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2 years ago
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How many molecules of ammonia are formed in the following equation: N2+3H2→2NH3
Katena32 [7]

Answer:

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Explanation:

The  balanced chemical equation provides information on:

  • <u>Reactants</u>: those are the compounds that appear of the left side of the equation, each with its chemical formula.

  • <u>Products</u>: those are the compounds that appear on the right side of the equation, again, each with its chemical formula.

  • <u>Ratio</u>: the coefficients of each compound (the number to the left of the chemical formula) represent the ratio of the number of molecules that react and are formed.

In the given equation you have:

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3 years ago
What is the specific heat of a substance if 25 grams rises in temperature from 10 degrees Celsius to 25 degrees with the additio
Marina86 [1]

Answer:

0.75 cal/g°c

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for specific heat we have formula:

Amount of heat absorbed or released = mass x specific heat of a substance x change in temperature.

ΔQ=m x c x ΔT

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so for specific heat,

c= ΔQ/mxΔT

c= 280/25x (25-10)

c= 280/375

c= 0.75 cal/g°c

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4 years ago
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