Calcium is used to isolate Rb from molten RbX because calcium has a smaller atomic radius than rubidium.
A chemical element's atomic radius, which is typically the average or typical distance between the nucleus's core and the outermost isolated electron, serves as a gauge for the size of an atom. There are numerous non-equivalent definitions of atomic radius since the border is not a clearly defined physical entity. Van der Waals radius, ionic radius, metallic radius, and covalent radius are the four most frequently used definitions of atomic radius. Atomic radii are typically measured in a chemically bound condition since it is challenging to isolated individual atoms in order to measure their radii individually.
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Answer:
All of the physical and biological factors in it's environment, I think this is the answer, but I might be wrong.
Explanation:
I learned it in my school's Science class
Answer:
The reaction would be 1500n (equal reaction)
Explanation:
This can be explained by Newton's third law of motion which states that for every action (force), there is an opposite and equal reaction. In other words, when two objects or people come in contact, the magnitude of force which they exert on each other is equal and they both feel an equal reaction force.
It doesn't matter whether one of the colliding bodies is of bigger mass than the other. This Newton's third law of motion is also known as the law of action and reaction.
After a radioactive atom decays, it is the same element that it
was before with no measurable change in mass. the decay that is present is
gamma decay because gamma decay has photons which has no mass unlike alpha and
beta decay.
The molar mass of the compound is 68 g/mol.
<h3>What is the molar mass?</h3>
The Osmotic pressure can be obtained from the relationship;
π= iCRT
π= osmotic pressure = 28.1 mmHg or 0.037 atm
i = Vant Hoff factor = 1
C = concentration = ?
R = gas constant = 0.082 atmLK-1Mol
T = temperature = 20°c + 273 = 293 K
C = π/iRT
C = 0.037/1 * 0.082 * 293
C = 0.0015 M
Now;
Number of moles = C/V = 0.0015/100 * 10^-3
= 0.015 moles
Number of moles = mass/molar mass
Molar mass = mass/Number of moles = 0. 102 g/ 0.015 moles = 68 g/mol
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