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Vikki [24]
3 years ago
15

How many grams of water are theoretically produced for the following reaction given we have 2.6 moles of HCl and 1.4 moles of Ca

(OH)2? Reaction: 2HCl + Ca(OH)2 → 2H2O + CaCl2 A) 25.2 B) 50.4 C) 46.8 D) 103.6 E) not enough information
Chemistry
1 answer:
leva [86]3 years ago
6 0

Answer:

The answer to your question is: 6.8 g of water

Explanation:

Data

2.6 moles of HCl

1.4 moles of Ca(OH)2

                           2HCl     +     Ca(OH)2    →        2H2O    +      CaCl2

MW                   2(36.5)               74                       36 g               111 g

                          73g                

                            1 mol of HCl ----------------  36.5 g

                           2.6 mol           --------------    x

                              x = (2.6 x 36.5) / 1   = 94.9 g

                           1 mol of Ca(OH)2 --------------   74 g

                         1.4 mol                  ---------------   x

                            x = (1.4 x 74) / 1  = 103.6 g

Grams of water

                        73 g of HCl ------------------   36g of H2O

                        94.9 g        -------------------    x

                     x = (94.9 x 36) / 73 = 46.8 g of water

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solution was prepared by dissolving 43.0 g of KCl in 225 g of water. Part A Calculate the mole fraction of the ionic species KCl
notka56 [123]

<u>Answer:</u> The mole fraction of KCl in the solution is 0.044

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

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Given mass of KCl = 43.0 g

Molar mass of KCl = 74.5 g/mol

Putting values in equation 1, we get:

\text{Moles of KCl}=\frac{43g}{74.5g/mol}=0.58mol

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Given mass of water = 225 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{225g}{18g/mol}=12.5mol

To calculate the mole fraction of a substance, we use the equation:

\chi_A=\frac{n_A}{n_A+n_B}

Moles of KCl = 0.58 moles

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Putting values in above equation:

\chi_{KCl}=\frac{n_{KCl}}{n_{KCl}+n_{\text{water}}}

\chi_{KCl}=\frac{0.58}{0.58+12.5}\\\\\chi_{KCl}=0.044

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4 years ago
How many moles are in .5g of sodium bromide?
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Answer: 4.86 x 10⁻³ mole.

Explanation:

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  • n is the number of moles, mass is the mass of the substance in g (m = 0.5 g), and molar mass of NaBr = 102.894 g/mole.
  • n = mass / molar mass = (0.5 g) / (102.894 g/mole) = 4.86 x 10⁻³ mole.
8 0
3 years ago
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