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Mandarinka [93]
3 years ago
13

What equation is the equation of the line that passes through (-10,8) and (5,5)

Mathematics
1 answer:
Fofino [41]3 years ago
6 0
The equation of the line is given by

y = mx + c

where m is the gradient of the line
c is where the line cuts the y-axis
x & y represent coordinates on the line.

The gradient m can be obtained as follows:

m = (5 - 8) / (5 - - 10) = (-3) / (15) = - 1/5

To obtain c, we use any known coordinate on the line and substitute it as well as the gradient in the general equation for the line.

Taking coordinates (5,5)

5 = (- 1/5)(5) + c

5 = - 1 + c

c = 6

Hence, the equation for this line is

y = -x/5 + 6
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denpristay [2]

Answer: have a good day :)

<em>the distance between the two points is 13.</em>

6 0
3 years ago
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Consider the function f(x) = x^{2/3} on the interval [-1,8].
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The right option is (c). The Mean Value Theorem does not apply since f(x) is not differentiable on (-1,8). Because the derivative of f is 2/3 x^(-1/3)  which is undefined at x=0.So, that would imply that it is not differentiable along the interval.
5 0
3 years ago
Rose bought a bag of potatoes for $6.00 and some granola bars for $5.25 per package. Her total bill was $74.25. How many package
neonofarm [45]

Answer:

Rose bought 14 packages of granola bars.

Step-by-step explanation:

Total bill = 1 bag of potatoes + x amount of packages of granola bars

Total bill = $74.25

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1 package of granola bar = 5.25

We set the equation to:

74.25 = 6.00 + 5.25x

Subtract 6.00 from both sides:

68.25 = 5.25x

Divide both sides by 5.25 to leave x by itself

68.25/5.25 = 5.25x/5.25

13 = x

This means Rose bought 13 packages of granola bars.

Let's recheck our work by inputting x = 13 into the equation:

74.25 = 6.00 + 5.25(13)

74.25 = 6.00 + 68.25

74.25 = 74.25

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2 years ago
Which of the following would be considered a monomial? Select all that apply
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Answer:

A and B

Step-by-step explanation:

Since these both only have one term and number/variable, making it a monomial.

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h=-16t^2+16t+320

6 0
3 years ago
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