Answer: A=750 +75*t
B=900 +25*t
There would be 975 students in each high school in year 3 when they are expected to have the same number of students.
Step-by-step explanation:
A = B
750 +75*t=900 + 25*t
Solving:
75*t -25*t= 900 - 750
50*t= 150
t=3
This indicates that in year 3 both High Schools are projected to have the same number of students. To get that amount, you simply replace this value in the expressions:
A=750 +75*t= 750 +75*3= 975
B=900 + 25*t=900 + 25*3= 975
There would be 975 students in each high school in year 3 when they are expected to have the same number of students.
Answer:1.00
Step-by-step explanation:
A=74-72/2.0
And I did it on kahn
5x(8-3)+3x-2
use the distributive property on 5x(8-3)
40x - 15x + 3x - 2
simplify
28x - 2
there's your answer
Answer:
40 apps
Step-by-step explanation:
12 sec ⇒ 8 apps
1 min = 60 sec
therefore, 60 sec ⇒ `60 x 8 / 12 = 40 apps
