Answer:
A. divide only on the right side of the equation by 2.
Step-by-step explanation:
I took the test yesterday and I got it hope this helps.
Answer:
Step-by-step explanation:
We have a right triangle with long side of 11in and smaller sides 14in/2=7in and h.
We know that
<u>Given</u>:
Given that the data are represented by the box plot.
We need to determine the range and interquartile range.
<u>Range:</u>
The range of the data is the difference between the highest and the lowest value in the given set of data.
From the box plot, the highest value is 30 and the lowest value is 15.
Thus, the range of the data is given by
Range = Highest value - Lowest value
Range = 30 - 15 = 15
Thus, the range of the data is 15.
<u>Interquartile range:</u>
The interquartile range is the difference between the ends of the box in the box plot.
Thus, the interquartile range is given by
Interquartile range = 27 - 18 = 9
Thus, the interquartile range is 9.
10/2 so 5 for 53, 10/4 so 5/2 or 2.5 for 54, and 10/3 or 3.333. For simplicity i divided everything by 10 to remove an extra zero but the answers would still be the same after you reduced
Step-by-step explanation:
Given,
Perimeter of the rectangle = 200cm
Breadth of the rectangle = 10 cm
Therefore, by the problem
=> 2(l+b) = 200cm
=> 2(l + 10) = 200cm
=> l + 10 = 100
=> l = 100 - 10
=> l = 90
<u>Hence, required length othe rectangle is 90 cm (Ans)</u>
