.325 mol KOH to grams

Predict whether a reaction occurs, and write balanced complete and net ionic equations:(a) Iron (III) chloride (aq) + cesium pho

Neporo4naja [7]

Answer : The balanced complete and net ionic equations are written below.

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a) The balanced molecular equation will be,

$FeCl_3(aq)+Cs_3PO_4(aq)\rightarrow 3CsCl(aq)+FePO_4(s)$

The complete ionic equation in separated aqueous solution will be,

$Fe^{3+}(aq)+3Cl^{-}(aq)+3Cs^{+}(aq)+PO_4^{3-}(aq)\rightarrow 3Cs^{+}(aq)+3Cl^{-}(aq)+FePO_4(s)$

In this equation the species present are, $3Cl^{-}\text{ and }Cs^{+}$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$Fe^{3+}(aq)+PO_4^{3-}(aq)\rightarrow FePO_4(s)$

(b) The balanced molecular equation will be,

$2NaOH(aq)+Cd(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+Cd(OH)_2(s)$

The complete ionic equation in separated aqueous solution will be,

$2Na^{+}(aq)+2OH^{-}(aq)+Cd^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^{+}(aq)+2NO_3^{-}(aq)+Cd(OH)_2(s)$

In this equation the species present are, $Na^{+}\text{ and }NO_3^{-}$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$Cd^{2+}(aq)+2OH^{-}(aq)\rightarrow Cd(OH)_2(s)$

(c) The balanced molecular equation will be,

$MgBr_2(aq)+2CH_3COOK(aq)\rightarrow (CH_3COO)_2Mg(aq)+2KBr(aq)$

The complete ionic equation in separated aqueous solution will be,

$Mg^{2+}(aq)+2Br^{-}(aq)+2K^{+}(aq)+2CH_3COO^{-}(aq)\rightarrow Mg^{2+}(aq)+2CH_3COO^{-}(aq)+2Br^{-}(aq)+2K^{+}(aq)$

In this equation all the species are the spectator ions.

Thus, there is no net ionic equation.

(d) The balanced molecular equation will be,

$Ag_2SO_4(aq)+BaCl_2(aq)\rightarrow 2AgCl(s)+BaSO_4(s)$

The complete ionic equation in separated aqueous solution will be,

$2Ag^{+}(aq)+SO_4^{2-}(aq)+Ba^{2+}(aq)+2Cl^{-}(aq)\rightarrow 2AgCl(s)+BaSO_4(s)$

In this equation no species are the spectator ions.

Thus, there is no net ionic equation.

(e) The balanced molecular equation will be,

$Na_2SO_4(aq)+Sr(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+SrSO_4(s)$

The complete ionic equation in separated aqueous solution will be,

$2Na^{+}(aq)+SO_4^{2-}(aq)+Sr^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^{+}(aq)+2NO_3^{-}(aq)+SrSO_4(s)$

In this equation the species present are, $Na^{+}\text{ and }NO_3^{-}$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$Sr^{2+}(aq)+SO_4^{2-}(aq)\rightarrow SrSO_4(s)$

5 0

3 years ago

50cm3 of 1 mol/dm3 HCl at 30°C was mixed with 50cm3 of 1mol/dm3 NaOH at 30°C in a styrofoam calorimeter. The temperature of the

trapecia [35]

Answer:

-21 kJ·mol⁻¹

Explanation:

Data:

H₃O⁺ + OH⁻ ⟶ 2H₂O

V/mL: 50 50

c/mol·dm⁻³: 1.0 1.0

ΔT = 4.5 °C

C = 4.184 J·°C⁻¹g⁻¹

C_cal = 50 J·°C⁻¹

Calculations:

(a) Moles of acid

$\text{Moles of acid} = \text{0.050 dm}^{3} \times \dfrac{\text{1.0 mol}}{\text{1 dm}^{3}} = \text{0.050 mol}\\\\\text{Moles of base} = \text{0.050 dm}^{3} \times \dfrac{\text{1.0 mol}}{\text{1 dm}^{3}} = \text{0.050 mol}$

So, we have 0.050 mol of reaction

(b) Volume of solution

V = 50 dm³ + 50 dm³ = 100 dm³

(c) Mass of solution

$\text{Mass of solution} = \text{100 dm}^{3} \times \dfrac{\text{1.00 g}}{\text{1 dm}^{3}} = \text{100 g}$

(d) Calorimetry

There are three energy flows in this reaction.

q₁ = heat from reaction

q₂ = heat to warm the water

q₃ = heat to warm the calorimeter

q₁ + q₂ + q₃ = 0

nΔH + mCΔT + C_calΔT = 0

0.050ΔH + 100×4.184×4.5 + 50×4.5 = 0

0.050ΔH + 1883 + 225 = 0

0.050ΔH + 2108 = 0

0.050ΔH = -2108

ΔH = -2108/0.0500

= -42 000 J/mol

= -42 kJ/mol

This is the heat of reaction for the formation of 2 mol of water

The heat of reaction for the formation of mol of water is -21 kJ·mol⁻¹.

5 0

3 years ago

Which process transfers heat from the ground to the air touching it? Conduction Convection Evaporation Radiation

Delicious77 [7]

Convection

Explanation:

Heat is a form of thermal energy borne as result of thermal energy. It is observed as temperature differences between places.

There are different types of heat transfer:

Conduction
Convection
Radiation

Conduction is a heat transfer which involves the actual movement of the collision of the molecules of the medium.

Convection is a heat transfer in fluids by their movement from areas of higher to places of lower heat.

Radiation is heat transfer using electromagnetism and does not involve molecules of the medium

The process of heat transfer from ground to the air touching it is convection. It involves particles of the air.

Learn more:

Convection brainly.com/question/1140127

#learnwithBrainly

8 0

3 years ago

Whenever anything moves, it has _____ energy. <br><br> chemical <br> heat <br> mechanical

BaLLatris [955]

Mechanical, because the other two make no sense and mechanical energy is the combination of kinetic and potential energy, or moving and still respectively.

5 0

3 years ago

What is the advantage of using Microsoft Excel to create a graph, as opposed to pen and paper?

natali 33 [55]

Answer:

the advantage of using Microsoft Excel to create a graph, as opposed to pen and paper is it will help you get the right answer

Explanation:

5 0

2 years ago