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Eddi Din [679]
3 years ago
11

HELP12 (a crossword that had 7 spaces)

Chemistry
1 answer:
german3 years ago
3 0
JJ Thompson discovered electrons
You might be interested in
1. The reaction below describes cellular respiration. Which compounds are the reactants and which are the
swat32

Answer:

C₆H₁₂O₆ and O₂ are reactant.

CO₂ and H₂O are products.

C₆H₁₂O₆ + 6O₂  →  6CO₂ + 6H₂O + ATP

Explanation:

There are two types of respiration:

1. Aerobic respiration  

2. Anaerobic respiration

Aerobic respiration

It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

Glucose + oxygen → carbon dioxide + water + 38ATP

Anaerobic Respiration

It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.  

Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide

This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.

Steps involve in anaerobic respiration are:

Glycolysis

Glycolysis is the first step of both aerobic and anaerobic respiration. It involve the breakdown of one glucose molecule into pyruvate and 2ATP.

Fermentation

The second step of anaerobic respiration is fermentation. It involve the fermentation of pyruvate into lactic acid or alcohol depending upon the organism in which it is taking place. There is no ATP produced, however carbon dioxide is released in this step.

8 0
3 years ago
Write the fraction of the mass of kcl produced from 1 g of k2c03​
Minchanka [31]

Mass of KCl= 1.08 g

<h3>Further explanation</h3>

Given

1 g of K₂CO₃

Required

Mass of KCl

Solution

Reaction

K₂CO₃ +2HCl ⇒ 2KCl +H₂O + CO₂

mol of K₂CO₃(MW=138 g/mol) :

= 1 g : 138 g/mol

= 0.00725

From the equation, mol ratio K₂CO₃ : KCl = 1 : 2, so mol KCl :

= 2/1 x mol K₂CO₃

= 2/1 x 0.00725

= 0.0145

Mass of KCl(MW=74.5 g/mol) :

= mol x MW

= 0.0145 x 74.5

= 1.08 g

6 0
3 years ago
Write the balanced net reaction for the following half cells: <br> Sn2+ / Sn<br> Cr2+ / Cr
GuDViN [60]

The balanced net reactiion for the following half cells will be

Sn + Cr²⁺   --->  Sn²⁺  +  Cr

<h3>What are Half cells ?</h3>

A half cell is one of the two electrodes of an electrochemical cell.

An electrochemical cell comprises two half cells, where every half cell contains an electrode and an electrolyte.

A salt bridge or direct contact is needed to connect two half cells.

The balanced net reactiion for the given half cells will be

Sn + Cr²⁺   --->  Sn²⁺  +  Cr

Learn more about Half cell here ;

brainly.com/question/1313684

#SPJ1

4 0
2 years ago
Which list best represents the flow of stimuli information in the body?
Vlad1618 [11]
The flow of stimuli information in the body is from the receptors to sensory neuron (afferent neurons) to the interneurons then to the central nervous system (brain and spinal cord) then is carried of by the motor neurons (efferent neurons) to the mucles involve.

Sensation to transduction to perception. Sensation is the ambiguous information which is received by the receptors or sensory organ henceforth, transduction occurs in the nerve cell protruding to the brain and is now called perception as the vague stimuli is interpreted and processed to be understood then is responded with the proper and apt response or reaction.

4 0
3 years ago
Draw an electrolytic cell in which Mn2+ is reduced to Mn and Sn is oxidized to Sn2+. (Assume standard conditions).
babunello [35]

Answer:

-1.05 V

Explanation:

A detailed diagram of the setup as required in the question is shown in the image attached to this answer. The electrolytes chosen are SnCl2 for the anode half cell and MnCl2 for the cathode half cell. Tin rod and manganese rod are used as the anode and cathode materials respectively. Electrons flow from anode to cathode as indicated. The battery connected to the set up drives this non spontaneous electrolytic process.

Oxidation half equation;

Sn(s) ------> Sn^2+(aq) + 2e

Reduction half equation:

Mn^2+(aq) + 2e ----> Mn(s)

Cell voltage= E°cathode - E°anode

E°cathode= -1.19V

E°anode= -0.14 V

Cell voltage= -1.19 V - (-0.14V)

Cell voltage= -1.05 V

8 0
3 years ago
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