Question

What is the equation of the line that passes through the point (9, 6) and is perpendicular to the line y = 3x - 5?

Answer 1

Answer:

Step-by-step explanation:

y = 3x - 5

m₁ = 3

The required line is perpendicular to y = 3x - 5. Let the required line's slope be m₂

m₂ = -1/m₁

m₂ = -1/3

Point (9,6)

Equation of line: y - y₁ = m(x - x₁)

y - 6 = (-1/3)(x - 9)

$y-6=\frac{-1}{3})x+\frac{1}{3}*9\\\\y-6=\frac{-1}{3}x+3\\\\y=\frac{-1}{3}x+3+6\\\\y=\frac{-1}{3}x+9$