What is the equation of the line that passes through the point (9, 6) and is perpendicular to the line y = 3x - 5?
1 answer:
Answer:
Step-by-step explanation:
y = 3x - 5
m₁ = 3
The required line is perpendicular to y = 3x - 5. Let the required line's slope be m₂
m₂ = -1/m₁
m₂ = -1/3
Point (9,6)
Equation of line: y - y₁ = m(x - x₁)
y - 6 = (-1/3)(x - 9)

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Answer:
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Step-by-step explanation:
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Answer:
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