Question

What is the magnitude of the momentum of a 3400 kg airplane traveling at a speed of 450 miles per hour?

Answer 1

Answer:

The magnitude of momentum of the airplane is $6.83\times 10^5\ kg-m/s$.

Explanation:

Given that,

Mass of the airplane, m = 3400 kg

Speed of the airplane, v = 450 miles per hour

Since, 1 mile per hour = 0.44704 m/s

v = 201.16 m/s

We need to find the magnitude of momentum of the airplane. It is given by the product of mas and velocity such that,

$p=mv$

$p=3400\ kg\times 201.16 \ m/s$

$p=683944\ kg-m/s$

or

$p=6.83\times 10^5\ kg-m/s$

So, the magnitude of momentum of the airplane is $6.83\times 10^5\ kg-m/s$. Hence, this is the required solution.

Answer 2

Answer:

p=m V

V= 450 mph=0.44*450 meters per second= 198 meters per second

p= 3400*198=673200 kg m/s (in SI units)

Explanation:

momentum is the product of mass and the velocity.

unit conversions are done in SI units