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2 years ago

You shake a bottle of soda and take off the cap. If the soda shoots out of the

Physics

2 answers:

Annette [7]2 years ago

4 0

Answer: B) 14.7 meters

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Explanation:

The bottle cap is a projectile, so we'll use the aptly named projectile formula

That formula (the meters version of it anyway) is approximately

h = -4.9t^2 + v*t + s

where,

t = elapsed time in seconds
h = height at time t
v = starting velocity
s = starting height

We'll assume that s = 0, though realistically it's probably going to be a bit larger than this (since the person is holding it above the ground). For the sake of simplicity, we'll stick with s = 0.

We're told that the initial velocity is 17 m/s, which means v = 17.

All of that means the formula mentioned earlier updates into this:

h = -4.9t^2 + 17t

If we were to graph this, or apply the -b/(2a) formula, then you should find that the vertex occurs when t = 1.73469 approximately.

Plug this into the equation we found to get...

h = -4.9t^2 + 17t

h = -4.9(1.73469)^2 + 17(1.73469)

h = 14.7449

h = 14.7

The bottle cap will reach a peak height of approximately 14.7 meters and does so at around the 1.7 second mark. The total flight time is approximately 2*1.7 = 3.4 seconds. This all assumes that the starting height and ending height are both 0 meters off the ground.

Harman [31]2 years ago

3 0

Answer:

A. 16.9 m

Explanation:

I think this is the answer i am not sure

but hope it helps

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Speed is a scalar quantity that describes only the

Anna [14]

Answer:

magnitude of the velocity

Explanation:

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2 years ago

A sailboat moves north for a distance of 10.00 km when blown by a wind from the exact south with a force of 5.00 x 10^4 n. how m

Nataliya [291]

Work is defined as the force times the distance which is mathematically expressed W = Fxd. The given force is 5x10^4 and the distance is 10000 m (the distance is converted as meter because Nm = J) the work done by the wind is W = 5x10^4 N (10000) = 500 x 10^6 Joules. I hope it answered your question

8 0

2 years ago

9. A 5.0 kg block on an inclined plane is acted upon by a horizontal force of 100 N shown in the figure below. The coefficient o

Helga [31]

Answer:

A: The acceleration is 7.7 m/s up the inclined plane.

B: It will take the block 0.36 seconds to move 0.5 meters up along the inclined plane

Explanation:

Let us work with variables and set

$m=5kg\\\\F_H=100N\\\\\mu=0.3\\\\\theta=37^o.$

As shown in the attached free body diagram, we choose our coordinates such that the x-axis is parallel to the inclined plane and the y-axis is perpendicular. We do this because it greatly simplifies our calculations.

Part A:

From the free body diagram we see that the total force along the x-axis is:

$F_{tot}=mg*sin(\theta)+F_s-F_Hcos(\theta).$

Now the force of friction is $F_s=\mu*N,$ where $N$ is the normal force and from the diagram it is $F_y=mg*cos(\theta).$

Thus $F_s=\mu*N=\mu*mg*cos(\theta).$

Therefore,

$F_{tot}=mg*sin(\theta)+\mu*mg*cos(\theta)-F_Hcos(\theta)\\\\=mg(sin(\theta)+\mu*cos(\theta))-F_Hcos(\theta).$

Substituting the value for $F_H,m,\mu, and \:\theta$ we get:

$F_{tot}= -38.63N.$

Now acceleration is simply

$a=\frac{F_H}{m} =\frac{-38.63N}{5kg} =-7.7m/s.$

The negative sign indicates that the acceleration is directed up the incline.

Part B:

$d=\frac{1}{2} at^2$

Which can be rearranged to solve for t:

$t=\sqrt{\frac{2d}{a} }$

Substitute the value of $d=0.50m$ and $a=7.7m/s$ and we get:

$t=0.36s.$

which is our answer.

Notice that in using the formula to calculate time we used the positive value of $a$ , because for this formula absolute value is needed.

5 0

3 years ago

Sana loved swimming.She joined a new smimmimg club .When she looked at the floor of the pool to estimate its depth she found tha

melisa1 [442]

Answer:

Refraction

Explanation:

When light passes from a rarer medium into a denser medium, it bends in the medium away from the normal. This creates the phenomenon of "apparent depth" as given in the question.

6 0

1 year ago

Explain why it is better to jump and land with bent knees rather than straight legs? Use key physics vocabulary.

BigorU [14]

Answer:

Bent knees

Explanation:

Depending the height your jumping from, if you were jumping from a high structure it's best if you jump and land on knees so you dont sprang your ankles from jumping and landing on your straight legs, you could even pull a muscle if you land on straight legs.

3 0

2 years ago