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juin [17]
3 years ago
8

g Question 11 pts A set of three vectors in R 4 could possibly be a linearly independent set of vectors. can never span R 4. can

never be a basis for R 4. Flag this Question Question 21 pts A set of vectors in R 3 spans R 3 but is not linearly independent. How many vectors can the set have
Mathematics
1 answer:
cricket20 [7]3 years ago
8 0

Answer:

Step-by-step explanation:

We will solve this questions using some dimensionality analysis.

a) Note that \mathbb{R}^4 is a vector space of dimension 4. So, given a set of three vectors, they could be or could not be linearly independent. However, if they were, they would not span \mathbb{R}^4 since in order for us to span \mathbb{R}^4 we need 4 or more vectors. Since a set of three vector cannot span this space, they automatically cant be a basis for \mathbb{R}^4.

b)  \mathbb{R}^3 has a dimension 3. So, for a set of vectors A to span this space, we need that A contains at least 3 vectors that are linearly independent. So A could have possibly infinite number of vectors as long as there is a subset of A that is composed by 3 linearly independent vectors.

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The City Housing Authority has received 75 applications from qualified applicants for nine low-income apartments. Four of the ap
butalik [34]
Total applications = 75
Apartments on north side of town = 4
Apartments on South side of town = 5

First  person has a 4/75 chance of getting a house in the north side
P(A) = 4/75

And second person has a 3/74 chance of getting a house in the north side
P(B) = 3/74

Probability that 2 qualified applicants will be selected for the north side of town =  P(A∩B) = P(A) x P(B) = (4 ÷ 75) x (3 ÷ 74) = 0.05333 x 0.04054 = 0.00216 

First  person has a 5/75 chance of getting a house in the south side 
P(A) = 5/75

And second person has a 4/74 chance of getting a house in the south side
P(B) = 4/74

Probability that 2 qualified applicants will be selected for the south side of town =  P(A∩B) = P(A) x P(B) = (5 ÷ 75) x (4 ÷ 74) = 0.06666 x 0.05405 = 0.00360


6 0
3 years ago
Solve each equation for y
blondinia [14]
The answer is number 6
7 0
3 years ago
Plz help... geometry volume, density
Ivenika [448]

From what I'm understanding of these questions, the biggest thing you need to answer these is the formulas for cylinders and triangular prisms. I'm not sure what the quantities are for either question so I'm going to work with made up numbers to give examples for the formulas. For number 2 with the cylinder, let's consider the formula first:

π × r2 × h    <em>OR    </em>pi (3.14) times radius squared times height

If you have the height and you have pi, all you need to take is the doubled radius (aka multiply it by 2) and plug that back into the formula. For the sake of an example, I'm going to make up the number 2 for the radius and 6 for the height. Here's what that would look like:

r = 2; double it, resulting in 4

pi x 4^2 x 6

3.14 x 16 x 6

= 301.44

Work with the actual numbers you have and you're good to go.

For number 3, reducing something by 1/2 means dividing by 2. Let's consider the formula and then work through another example:

1/2 x b x h x l   <em>OR </em>   1/2 times base times height times length

For the sake of an example, I'll use 10 for the height, 15 for the base, and 20 for the length:

h = 10; reduce by 1/2, resulting in 5

1/2 x 15 x 5 x 20

= 750

Plug in your actual quantities, and remember your volume units. Hope this helps!

4 0
3 years ago
1x10 to the fifth power over 4x10 to the negative faith power given on scientific notation
MissTica

Answer:

2.5*10^{8}

Step-by-step explanation:

<u><em>The correct question is</em></u>

1x10 to the fifth power over 4x10 to the negative fourth power given on scientific notation

we know that

To divide two numbers in scientific notation, divide their coefficients and subtract their exponents.

we have

\frac{1*10^{5}}{4*10^{-4}}=(\frac{1}{4})*10^{5+4} =0.25*10^{9}= 2.5*10^{8}

8 0
3 years ago
In Rivertown High School, about 30% of the students buy a raffle ticket. Given that a student buys a raffle ticket, there is a 1
lesya [120]

The probability that that a randomly selected student will buy a raffle ticket and win a prize = 0.03

Step-by-step explanation:

Step 1 :

Given,

The percentage of students buying the raffle ticket = 30%

The percentage that the student who bought the ticket wins the prize = 10%

We need to determined the probability that randomly selected student will buy a raffle ticket and win a prize.

Step 2 :

The probability that a student buys the raffle ticket =  \frac{30}{100}  = \frac{3}{10}

The probability that a student wins a prize = \frac{10}{100} = \frac{1}{10}

The probability that a student who buys the ticket wins a price can be computed by taking the product of the above 2 probabilities.

 = \frac{3}{10} × \frac{1}{10}  = \frac{3}{100} = 0.03

Step 3 :

Answer :

The probability that that a randomly selected student will buy a raffle ticket and win a prize = 0.03

6 0
3 years ago
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