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Vesna [10]
3 years ago
9

The mass of an unidentified rock is 40 grams. Students determine the volume of the rock by placing the rock in a cylinder with w

ater. The students calculate the density of the rock. They determine the identity of the rock based on the density ranges in the table.

Chemistry
1 answer:
insens350 [35]3 years ago
7 0

Answer:

A. Coal

Explanation:

Volume_{rock} = water displaced by rock

Water displaced by rock = volume of water after rock is dropped into the cylinder - volume of water before the rock was dropped into the water

Water displaced by the rock = 180 ml - 150 ml = 30 ml

Volume_{rock} = 30 ml

Density of rock:

40 grams => 30 ml

x grams => 1 ml

Cross multiply

1*40 = 30*x

40 = 30x

40/30 = 30x/30

1.3 = x

Density of rock = 1.3 g per 1 ml

Recall: 1 ml = 1 cm³

Therefore,

Density of the rock = 1.3 g/cm³

1.3 g/cm³ falls within the range of 1.1 - 1.4 g/cm³

Therefore, the rock is identified as Coal.

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When a calcium atom forms an ion, it loses two electrons. what is the eletrical charge ofbthe calcium ion?
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Answer:

A

Explanation:

because it loses 2 electrons

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How does electronegativity affect the polarity of the bond between two atoms?
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It can allow the molecule (like water) to be polar because it has a negative and positive side to it (oxygen holds the negatives tight causing the hydrogens to be positive).
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Which condition increases the number of collisions between reactant molecules in a given volume?
Nezavi [6.7K]

Answer:

Increasing Surface Area

Explanation:

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The number of electrons in a neutral atom is equal to the number of protons? True or false
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true

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in order for the atom to be neutral the number of protons and electrons have to be the same.

3 0
2 years ago
2. Calculate the mass of 3.47x1023 gold atoms.
lapo4ka [179]

3.47 x 10^{23} atoms of gold have mass of 113.44 grams.

Explanation:

Data given:

number of atoms of gold = 3.47 x 10^{23}

mass of the gold in given number of atoms = ?

atomic mass of gold =196.96 grams/mole

Avagadro's number = 6.022 X 10^{23}

from the relation,

1 mole of element contains 6.022 x 10^{23} atoms.

so no of moles of gold given = \frac{3.47 X 10^{23}  }{6.022 X 10^{23} }

0.57 moles of gold.

from the relation:

number of moles = \frac{mass}{atomic mass of 1 mole}

rearranging the equation,

mass = number of moles x atomic mass

mass = 0.57 x 196.96

mass = 113.44 grams

thus, 3.47 x 10^{23} atoms of gold have mass of 113.44 grams

3 0
3 years ago
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