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Helen [10]
3 years ago
6

Mechanical energy is the sum of the _____ energy of an object. A kinetic and potential B potential and thermal C kinetic and che

mical D potential and chemical
Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
5 0

Answer:

A. kinetic and potential

Explanation:

kinetic energy (energy of motion) or potential energy (stored energy of position)

- Hope that helped! Let me know if you need further explanation.

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Selfmade.ivyy hope this help
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In TEN complete sentences, describe how the LAW OF CONSERVATION applies to the stuff YOU OWN. For example: In real life, can new
satela [25.4K]

Answer:

Both the initial and final substances are composed of atoms because all matter is composed of atoms. According to the law of conservation of matter, matter is neither created nor destroyed, so we must have the same number and type of atoms after the chemical change as were present before the chemical change.

Explanation:

The atoms that make up your body were produced inside a star and have ... I read once that atoms get recycled so much through the planet that each of ... from William Shakespeare, but I do know this: All of us come from stars. ... If you have gold fillings in your teeth, those atoms came from a star explosion.

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3 years ago
The ________ molecules which form the bilayer region of the cell membrane have hydrophilic regions on the outer surface and hydr
Goshia [24]

Answer:

The answer is: phospholipid molecules

Explanation:

The plasma membrane of a cell is consists of a lipid bilayer. This lipid bilayer, also known as the phospholipid bilayer, is a polar membrane composed of two layers of lipid molecules, usually amphipathic phospholipid molecules.

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ASAP PLEASEE
Lesechka [4]

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Joe Mama Formula

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JoeMamic Acid is the answer

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g Enter your answer in the provided box. If 30.8 mL of lead(II) nitrate solution reacts completely with excess sodium iodide sol
Ronch [10]

Answer:

M=0.0637M

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

Pb(NO_3)_2(aq)+2NaI(aq)\rightarrow PbI_2(s)+2NaNO_3(aq)

Thus, for 0.904 g of precipitate, that is lead (II) iodide, we can compute the initial moles of lead (II) ions in lead (II) nitrate:

n_{Pb^{2+}}=0.904gPbI_2*\frac{1molPbI_2}{461gPbI_2}*\frac{1molPb(NO_3)_2}{1molPbI_2}  *\frac{1molPb^{2+}}{1molPb(NO_3)_2} =1.96x10^{-3}molPb^{2+}

Finally, the resulting molarity in 30.8 mL (0.0308 L):

M=\frac{1.96x10^{-3}molPb^{2+}}{0.0308L}\\ \\M=0.0637M

Regards.

3 0
3 years ago
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