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denis23 [38]
4 years ago
13

Consider the following two substances and their vapor pressures at 298 K.

Chemistry
2 answers:
Vadim26 [7]4 years ago
8 0

Answer:

Based on the information, the comparison of characteristics of two substances is as follow:

Substance A:

  • Has a higher boiling point
  • Has a higher heat of vaporization

Substance B:

  • Has weaker intermolecular forces
  • Is a gas at 300 mmHg

Explanation:

  • The substance A has vapor pressure 275 mmHg so it has low vapor as compared to substance B so it has higher boiling point and has higher heat of vaporization.
  • The substance B has vapor pressure of 459 mmHg so it has weaker intermolecular forces as compared to substance A and also it is a gas at 300 mmHg.    

Lady bird [3.3K]4 years ago
4 0

Answer:

Comparing the two substances, A and B

a) B has weaker in intermolecular forces.

b) A has a higher boiling point.

c) B is a gas at 300mmHg.

d) A has a higher heat of vaporization

The reason for this is because vapour pressure is the measure of the pressure exerted by a gas above a liquid in a closed container. Strong intermolecular forces produce a lower rate of evaporation and a lower vapor pressure. Weak intermolecular forces produce a higher rate of evaporation and a higher vapor pressure.

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5.625 atm will be the pressure of the gas at 250 K temperature of the gas at constant volume.

<h3>How we calculate the pressure of the gas?</h3>

Pressure of the gas will be calculated by using the ideal gas equation as:

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From the question, it is clear that:

Moles of the gas and volume is constant here, so we calculate the pressure by rearranging the above equation as:

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And required equation will be:

P₁/T₁ = P₂/T₂, where

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Hence, 5.625 atm is the pressure of the gas.

To know more about ideal gas equation, visit the below link:

brainly.com/question/1056445

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