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4 years ago

Consider the following two substances and their vapor pressures at 298 K.

Chemistry

2 answers:

Vadim26 [7]4 years ago

8 0

Answer:

Based on the information, the comparison of characteristics of two substances is as follow:

Substance A:

Has a higher boiling point
Has a higher heat of vaporization

Substance B:

Has weaker intermolecular forces
Is a gas at 300 mmHg

Explanation:

The substance A has vapor pressure 275 mmHg so it has low vapor as compared to substance B so it has higher boiling point and has higher heat of vaporization.
The substance B has vapor pressure of 459 mmHg so it has weaker intermolecular forces as compared to substance A and also it is a gas at 300 mmHg.

Lady bird [3.3K]4 years ago

4 0

Answer:

Comparing the two substances, A and B

a) B has weaker in intermolecular forces.

b) A has a higher boiling point.

c) B is a gas at 300mmHg.

d) A has a higher heat of vaporization

The reason for this is because vapour pressure is the measure of the pressure exerted by a gas above a liquid in a closed container. Strong intermolecular forces produce a lower rate of evaporation and a lower vapor pressure. Weak intermolecular forces produce a higher rate of evaporation and a higher vapor pressure.

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3 years ago

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3 years ago

Why is Cu+O=2CuO unbalanced

stepan [7]

Answer:

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Explanation:

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3 0

3 years ago

Read 2 more answers

The painkiller, Advil® contains the active ingredient ibuprofen (IB), which has a pKb of

denis23 [38]

This problem is providing the basic dissociation constant of ibuprofen (IB) as 5.20, its pH as 8.20 and is requiring the equilibrium concentration of the aforementioned drug by giving the chemical equation at equilibrium it takes place. The obtained result turned out to be D) 4.0 × 10−7 M, according to the following work:

First of all, we set up an equilibrium expression for the given chemical equation at equilibrium, in which water is omitted for it is liquid and just aqueous species are allowed to be included:

$Kb=\frac{[IBH^+][OH^-]}{[IB]}$

Next, we calculate the concentration of hydroxide ions and the Kb due to the fact that both the pH and pKb were given:

$pOH=14-8.20=5.80$

$[OH^-]=10^{-5.8}=1.585x10^{-6}M$

$Kb=10^{-5.20}=6.31x10^{-6}$

Then, since the concentration of these ions equal that of the conjugated acid of the ibuprofen (IBH⁺), we can plug in these and the Kb to obtain:

$6.31x10^{-6}=\frac{(1.585x10^{-6})(1.585x10^{-6})}{[IB]}$

Finally, we solve for the equilibrium concentration of ibuprofen:

$[IB]=\frac{(1.585x10^{-6})(1.585x10^{-6})}{6.31x10^{-6}}=4.0x10^{-7}$

Learn more:

(Weak base equilibrium calculation) brainly.com/question/9426156

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3 years ago