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Law Incorporation [45]
3 years ago
8

NEED NOW!

Chemistry
2 answers:
Ann [662]3 years ago
7 0

A. a Community - apex



vfiekz [6]3 years ago
6 0
It's either genus or species. I'd go with Genus
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Out of 13 students how many<br> saw themselves in the<br> horoscope?
Andru [333]

Answer: Astrology is not astronomy! ... Astronomers and other scientists know that stars many light years* away have no effect on the ... Imagine a straight line drawn from Earth through the Sun and out into space way ... The 13 constellations in the zodiac. ... on the phases of the Moon), each month got a slice of the zodiac all to itself.

Explanation: Hope this helps

5 0
3 years ago
What is the relative humidity of the air when the dry-bulb temperature is 4°C and the dewpoint is -4°C?
boyakko [2]

Answer:56%

Explanation:

In the dewpoint chart when you line it up it ends up at 56%

3 0
3 years ago
Imagine that you're doing an experiment that requires you to smell the odor of a chemical solution in a beaker. Which procedure
Alex787 [66]
The correct answer is (a) wave the fumes toward your nose with your hand. If you smell the chemicals directly, it could be harmful too your health, especially if they are strong. Also remember to <em>never </em>smell chemicals unless you are being told to do so.
8 0
3 years ago
Read 2 more answers
11.0 L of hydrogen and 5.52 L of oxygen are exploded together in a reaction tube. What volume of water vapor was formed, at STP?
Marysya12 [62]

Answer:

11.0 L

Explanation:

The equation for this reaction is given as;

2H2  +  O2  -->  2H2O

2 mol of H2 reacts with 1 mol of O2 to form 2 mol of H2O

At STP;

1 mol = 22.4 L

This means;

44.8 L of H2 reacts with 22.4 L of O2 to form 44.8 L of H2O

In this reaction, the limiting reactant is H2 as O2 is in excess.

The relationship between H2 and H2O;

44.8 L = 44.8 L

11.0 L would produce x

Solving for x;

x = 11 * 44.8 / 44.8

x = 11.0 L

4 0
3 years ago
Calculation of Molar Ratios of Conjugate Base to Weak Acid from pH For a weak acid with a pKa of 6.0, calculate the ratio of con
Free_Kalibri [48]

Explanation:

According to the Handerson equation,  

          pH = pK_{a} + log \frac{\text{salt}}{\text{acid}}

or,      pH = pK_{a} + log \frac{\text{conjugate base}}{\text{acid}}

Putting the given values into the above equation as follows.

     pH = pK_{a} + log \frac{\text{conjugate base}}{\text{acid}}

       5.0 = 6.0 + log \frac{\text{conjugate base}}{\text{acid}}[/tex]

      log \frac{\text{conjugate base}}{\text{acid}} = -1.0

or,      \frac{\text{conjugate base}}{\text{acid}} = 10^{-1.0}

                            = 0.1

Therefore, we can conclude that molar ratios of conjugate base to weak acid for given solution is 0.1.

7 0
3 years ago
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